Answer:
b) 0.0608
Step-by-step explanation:
As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed
Therefore the rain probability is
where,
T = Length of the time interval
Plus, as we know that rain is independent
So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes
i.e
= 5.91666 hours long.
So, P1 should be
= 0.2465
Now we assume the probability of rain on day 2 is P2
So it would be same i.e 0.2465
Since these events are independent
So, the total probability is
= 0.0608
Hence, the b option is correct
Let us assume the cost of a soft drink = x dollars
Value of the gift certificate that Angela had = $5
Cost of the movie ticket = $10
Cost of a medium popcorn = $5.50
Then
27.90 + 5 = 2(10) + 2(5.50) + x
32.90 = 20 + 11 + x
32.90 = 31 + x
x = 1.90 dollars
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or $1.90.
m□ebd=4 x-8 and m□ebc=5 x+20
This is solvable only if e b is the initial side and b d and b c lies on opposite side of each other and lies on a line i.e c,b,d are Collinear.
∠ebd and ∠ebc will form a linear pair.The meaning of linear pair is that angles forming on one side of a straight line through a common vertex which are adjacent is 180°.
i.e
∠ ebd + ∠ebc = 180°
4 x- 8 + 5x + 20= 180°
adding like terms
⇒ 9 x +12 =180°
⇒ 9 x = 180° - 12
⇒ 9 x = 168°
⇒ x =( 168/9)°=(56/3)°
now m□ebc =5 x +20
= 5 × 56/3 + 20
= 280/3 + 20
=340/3
m□ebc=( 340/3)°
So, solution set is x =(56/3)° and m□ebc =(340/3)°
Answer:
There is no significant evidence which shows that there is a difference in the driving ability of students from West University and East University, <em>assuming a significance level 0.1</em>
Step-by-step explanation:
Let p1 be the proportion of West University students who involved in a car accident within the past year
Let p2 be the proportion of East University students who involved in a car accident within the past year
Then
p1=p2
p1≠p2
The formula for the test statistic is given as:
z=
where
- p1 is the <em>sample</em> proportion of West University students who involved in a car accident within the past year (0.15)
- p2 is the <em>sample</em> proportion of East University students who involved in a car accident within the past year (0.12)
- p is the pool proportion of p1 and p2 (
) - n1 is the sample size of the students from West University (100)
- n2 is the sample size ofthe students from East University (100)
Then we have z=
≈ 0.6208
Since this is a two tailed test, corresponding p-value for the test statistic is ≈ 0.5347.
<em>Assuming significance level 0.1</em>, The result is not significant since 0.5347>0.1. Therefore we fail to reject the null hypothesis at 0.1 significance
