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2 years ago

The sum of two numbers is 80. The larger number is four more than three times the smaller number. Find both numbers.

Mathematics

1 answer:

nexus9112 [7]2 years ago

3 0

Let the smaller number = X

Then the larger number is 3x+4 ( four more than 3 times the smaller number)

The sum of both numbers = 80

so you have X + 3X+4 = 80

Simplify the left side:

4x+4 = 80

Subtract 4 from each side:

4x = 76

Divide both sides by 4:

X = 76/4

X = 19

The smallest number is 19

The largest number is 80 - 19 = 61 ( check: 3*19 = 57+4 = 61)

The two numbers are 19 and 61

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Read 2 more answers

The square of a number decreased by 3 times the number 28 find all possible values for the number

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Question:

The square of a number decreased by 3 times the number is 28 find all possible values for the number

Answer:

The possible values of number are 7 and -4

Solution:

Given that the square of a number decreased by 3 times the number is 28

To find: all possible values of number

Let "a" be the unknown number

From given information,

square of a number decreased by 3 times the number = 28

$a^2 - 3a = 28$

$a^2 - 3a - 28 = 0$

Let us solve the above quadratic equation

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

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Thus the possible values of number are 7 and -4

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