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Black_prince [1.1K]
2 years ago
12

Uma empresa transporta armários para escritórios para uma localidade distante 425km. Seu custo é de R$2,10 por km rodado. Quando

os armários vão montados, a capacidade do veículo é de 60 unidades. Quando eles são desmontados a capacidade aumenta 6 vezes. Pede-se: 1- Qual o custo por armário montado? 2- Qual a economia por armário, quando esses são levados desmontados?
Mathematics
1 answer:
MariettaO [177]2 years ago
8 0

Answer:

1.  <u>$14.88</u>

2.  <u>$12.40</u>

Step-by-step explanation:

An english translation:

<em>A company transports office cabinets to a location 425km away. Its cost is R $ 2.10 per km traveled. When the cabinets are assembled, the vehicle's capacity is 60 units. When they are disassembled the capacity increases 6 times. We ask: 1- What is the cost per assembled cabinet? 2- What is the savings per cabinet, when these are taken apart.</em>

<em />

<u>Solution:</u>

425 km with 2.10 per km means:

425 * 2.10 = $892.50 total cost

Now, when assembled, there goes 60 cabinets, so cost per assembled cabinet is:

<u>Cost per assembled cabinet = 892.5/60 = $14.875 = $14.88</u>

<u></u>

The capacity of 60 after disembling, it becomes:

60 * 6 = 360

So, cost per cabinet becomes:

892.5/360 = <u>$2.48</u>

The savings is how much you save up if they were assembled:

14.88 - 2.48 = <u>$12.40</u>

<u>Savings = $12.40</u>

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9x - 2y = 11 ... (i)

5x - 2y = 15 ... (ii)

Subtracting equation (ii) from (i) we get;

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Replacing x = -1 in equation (i) we get;

9(-1) - 2y = 11

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Step-by-step explanation:

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Angela has the following coins in her pocket:
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Answer:

  • There are 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

Explanation:

The possible combinations are:

1. Assuming the first coin is 10p:

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  • (10p, 2p)
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2. Asuming the first coin is 1p

Do not count (1p, 10p) as it is the same combination as (10p, 1p)

  • (1p, 50p)
  • (1p, 2p)
  • (1p, 20p)

3. Assuming the first coin is 50p:

Do not count (50p, 10p) nor (50p, 1p) as they are the same combinations (10p, 50p) and (1p, 50p) counted earlier:

  • (50p, 2p)
  • (50p, 20p)

4. Assuming the first coin is 2p:

The only new combination is:

  • (2p, 20p)

5. All the combinations with 20p have already been listed.

Therefore:

  • There are 4 + 3 + 2 + 1 = 10 different combinations

  • The list of different combinations is:

        (10p, 1p), (10p, 50p), (10p, 2p), (10p, 20p), (1p, 50p), (1p, 2p),

        (1p, 20p), (50p, 2p), (50p, 20p), (2p, 20p)

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Answer:

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(D)The mean number of points per player per game is the same at all 3 schools.

Step-by-step explanation:

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6 players who each score 0 points per game.

The Scores are: 0,0,0,0,0,0,12,12,12,12,12,12

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<u>University of Maryland</u>

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The following applies:

(B) At Maryland, the mean number of points per player per game is greater than the median number of points per player per game.

(D)The mean number of points per player per game is the same at all 3 schools.

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