Quadratic equation that contain the three ordered pairs <br> (1,6), (3,26), (-2,21)

19.Find the median of the distribution 5,9,8,6,3,5,7,12 and 13<br>1<br>-

77julia77 [94]

Answer:

Your answer is 7

Step-by-step explanation:

First place the numbers in order from lest to greatest, then use your two index fingers to find the middle number from all the numbers, like this:

3, 5, 5, 6, <u>7</u>, 8, 9, 12, 13

P.S. is the number "1" part of the numbers? Because if it is then you need to do the same thing of ordering the numbers and if there are two numbers in between, all you have to do is add & divide.

1, 3, 5, 5, <u>6, 7</u>, 8, 9, 12, 13

6 + 7 = 13; 13/2 = 6.5

If that's the case, then your answer is 6.5.

7 0

2 years ago

Ryan found that the amount of plant food remaining decreased an equal amount each day, and he used the entire 72 milliliters by

BaLLatris [955]

Answer:

A function rule for the relationship between the amount of plant food remaining, f(x), and the number of days that have passed, x is $f(x)=72-12x$

Step-by-step explanation:

We are given that Ryan used 72 mL of food over the course of a 6 day study.

So, He used amount per day = $\frac{72}{6}$

He used amount per day =12 ml/day

Now we are given that t the amount of plant food remaining decreased an equal amount each day, and he used the entire 72 milliliters by the end of his study.

So, The equation becomes : f(x)=72-12x

f(x):The amount of plant food remaining

x : The number of days that have passed

Hence a function rule for the relationship between the amount of plant food remaining, f(x), and the number of days that have passed, x is $f(x)=72-12x$

4 0

2 years ago

A boat sails on a bearing of 038°anf then 5km on a bearing of 067°.

I am Lyosha [343]

This question is not complete

Complete Question

A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point

Answer:

a)8.717km

b) 54.146°

Step-by-step explanation:

(a)how far is the boat from its starting point.

We solve this question using resultant vectors

= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)

Where

Rcos θ = x

Rsinθ = y

= (4cos38,4sin38) + (5cos67,5sin67)

= (3.152, 2.4626) + (1.9536, 4.6025)

= (5.1056, 7.065)

x = 5.1056

y = 7.065

Distance = √x² + y²

= √(5.1056²+ 7.065²)

= √75.98137636

= √8.7167296826

Approximately = 8.717 km

Therefore, the boat is 8.717km its starting point.

(b)calculate the bearing of the boat from its starting point.

The bearing of the boat is calculated using

tan θ = y/x

tan θ = 7.065/5.1056

θ = arc tan (7.065/5.1056)

= 54.145828196°

θ ≈ 54.146°

7 0

2 years ago

_____ are ______ midsegments of ΔWXY.

iVinArrow [24]

Answer:

The perimeter of Δ WXY is 14.50 cm ⇒ the last answer

Step-by-step explanation:

* Lets explain how to solve the problem

- There is a fact in any triangle; the segment joining the midpoints of

two side of a triangle is parallel to the 3rd side and half its length

* Lets use this fact to solve the problem

- In Δ WXY

∵ Q is the midpoint of WX

∵ R is the midpoint of XY

∵ S is the midpoint of YW

- By using the fact above

∴ QR = 1/2 WY

∴ RS = 1/2 WX

∴ SQ = 1/2 XY

- Lets calculate the length of the sides of Δ WXY

∵ QR = 1/2 WY

∵ QR = 2.93

∴ 2.93 = 1/2 WY ⇒ multiply both sides by 2

∴ WY = 5.86 cm

∵ RS = 1/2 WX

∵ RS = 2.04

∴ 2.04 = 1/2 WX ⇒ multiply both sides by 2

∴ WX = 4.08 cm

∵ SQ = 1/2 XY

∵ SQ = 2.28

∴ 2.28 = 1/2 XY ⇒ multiply both sides by 2

∴ XY = 4.56 cm

- Lets find the perimeter of Δ WXY

∵ The perimeter of Δ WXY = WX + XY + YW

∴ The perimeter of Δ WXY = 5.86 + 4.08 + 4.56 = 14.50

* The perimeter of Δ WXY is 14.50 cm

3 0

2 years ago

Read 2 more answers

Which input value produces the same output value for the two functions on the graph?

Darya [45]

<h3>Answer:</h3>

x = -2

<h3>Explanation:</h3>

The line represents the output value (y) for a given input value (x). Where the lines cross, the output values are equal. These lines cross at x=-2.

4 0

2 years ago

Read 2 more answers

Quadratic equation that contain the three ordered pairs (1,6), (3,26), (-2,21)