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cupoosta [38]
1 year ago
14

Quadratic equation that contain the three ordered pairs (1,6), (3,26), (-2,21)

Mathematics
1 answer:
rosijanka [135]1 year ago
8 0
Y= 3x^2-2x+5

6= 3(1)^2-2(1)+5
6= 3-2+5
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What is the unit price of 8 mugs for $38.32
jarptica [38.1K]

Answer:

4.79$ for each mug

Step-by-step explanation:

38.32/8 = 4.79 and to double-check do 4.79*8

8 0
1 year ago
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Rachel created 215 pairs of earrings. Material for the earrings were $0.25 a pair. At a craft fair rachel sells all 215 pairs of
Stels [109]

Answer: 14.97 per pair of earrings

Step-by-step explanation:

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2 years ago
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in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru
melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is  

n = 200

the proportion is

p = 154/200 = 0.77

<em>Since both np ≥ 10 and n(1-p) ≥ 10 </em>

<em>We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant  difference. </em>

The approximation would be to a Normal curve with this parameters:

<em>Mean </em>

p = 0.77

<em>Standard deviation </em>

\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298

The 90% confidence interval for the proportion would be then  

\bf  [0.77-z^*0.0298, 0.77+z^*0.0298]

where \bf z^* is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval \bf [-z^*,z^*] is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

<em>NORMSINV(0.95) and we get a value of 1.645 </em>

The 90% confidence interval for the proportion is then

\bf  [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0
2 years ago
it is sixty-eight kilometres between venice and vicenza. every day the train does the journey four times. how far does the train
myrzilka [38]
68×4≈272. easy use ur calculator ii will help u more. have fun ejoy ur day
8 0
1 year ago
Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4
german

Answer:

range is  between 55.5 to 64.5

Step-by-step explanation:

Horn lengths of Texas longhorn cattle are normally distributed. The mean horn spread is 60 inches with a standard deviation of 4.5 inches

68% is 1 standard deviation from mean

To get the range of 1 standard deviation we add and subtract standard deviation from mean

mean = 60

standard deviation = 4.5

60 - 4.5= 55.5

60+4.5 = 64.5

1 standard deviation is between 55.5 to 64.5

That is 68% range is  between 55.5 to 64.5

8 0
2 years ago
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