For this case we have the following equation:
From here, we must substitute ordered pairs of the form:
(x, y)
If the ordered pair satisfies the equation, then it belongs to the line.
We have then:
For (8, 5):
We substitute the following values:
We observe that the equation is not satisfied and therefore, this point does not belong to the line.
Since one of the points does not belong to the line, then the equation is not a good model.
Answer:
It is not a good model. One of the points does not belong to the line.
Answer:
6 units
Step-by-step explanation:
Given: Points H and F lie on circle with center C. EG = 12, EC = 9 and ∠GEC = 90°.
To find: Length of GH.
Sol: EC = CH = 9 (Radius of the same circle are equal)
Now, GC = GH + CH
GC = GH + 9
Now In ΔEGC, using pythagoras theorem,
......(ΔEGC is a right triangle)
Now, Let GH = <em>x</em>
On rearranging,
So x = 6 and x = - 24
∵ x cannot be - 24 as it will not satisfy the property of right triangle.
Therefore, the length of line segment GH = 6 units. so, Option (D) is the correct answer.
Add the order of pizzas together and divide by four. Round your answer.
Answer:
Percentage Rate=6%
Step-by-step explanation:
Total borrowed=$2,100
Time=3 years
Rate=?
Total amount owed after 3 years= total borrowed + simple interest
$2,478=$2,100 + x
X=$2,478 - $2,100
=$378
The simple interest=$378
Simple interest=P×R×T
Where,
P= principal=$2,100
R=Rate=?
T=Time=3 years
Simple interest=$378
Simple interest=P×R×T/100
$378=$2,100×R×3/100
$378=$6,300R/100
$378=$63R
R=$378/$63
R=6
Therefore,
Rate=6%
Answer:
< CFE = 40°
Step-by-step explanation:
To better understand the solution, see attachment for the diagram.
Given:
BC parallel to DE
Measure of Arc BD = 58°
Measure of Arc DE = 142°
First step: Draw a diameter that passes through the centre of the circle and name it. In this case, the diameter is line ST.
The line ST divides the arc BD and arc DE into half.
That is:
Arc SC = 1/2(arc BC) =1/2(58)
Arc SC = 29°
Arc TE = 1/2(arc DE) =1/2(142)
Arc TE = 71°
Arc SC + Arc CE + Arc TE = 180° (Sum of angles in a semicircle
29° + Arc CE + 71° = 180°
Arc CE + 100° = 180°
Arc CE = 180-100
Arc CE = 80°
Inscribed angle = 1/2(intercepted angle)
<CFE = 1/2(Arc CE )
<CFE = 1/2(80)
< CFE = 40°
