All categories

2 years ago

Ben has 18 pears. Sophia has a number of pears two less than Ben. How many pears Sophia has?

Mathematics

2 answers:

densk [106]2 years ago

8 0

Sophia = Ben - 2
Sophia = 18 - 2
Sophia = 16

In short, She has 16 pears

Hope this helps!

Serggg [28]2 years ago

7 0

18 pears subtract by 2 wich will equal 16 pears...

18-2=16

You might be interested in

In 2003, the Accreditation Council for Graduate Medical Education (ACGME) implemented new rules limiting work hours for all resi

Alborosie

Answer:

80.67 hours

Step-by-step explanation:

Data provided in the question:

The number of weekly hours worked :

78 85 82 79 77 82 81 82 81 81 82 78

total number of observations = 12

Now,

Mean = (Sum of all the data values) ÷ (Total number of data values)

Mean = ( 78 + 85 + 82 + 79 + 77 + 82 + 81 + 82 + 81 + 81 + 82 + 78 ) ÷ 12

Mean = 968 ÷ 12

or Mean = 80.67 hours

8 0

2 years ago

There are 12 boys and 16 girls in a classroom. which represents the simplified ratio of girls to students in the classroom?

Papessa [141]

The unsimplified version is 12:16
you have to find the highest common factor in them
in this case it would be 4
divide both numbers by 4
3:4

hope this helps you

3 0

2 years ago

Read 2 more answers

Please help !!!! Joe runs 8.25 times around a track in 1,119.803 seconds. If one lap around the track is 402.3 meters, which is

Sloan [31]

Answer: The answer is 3m/s

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The owners of Prim's Pizza are concerned that many of their customers are starting to purchase pizza from The Pizza Palace becau

AleksandrR [38]

Answer:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

Step-by-step explanation:

We have the following info given:

$\bar X_1 = 240$ sample mean for medium Pizzas from Prim's

$\bar X_2 = 210$ sample mean for medium Pizzas from Pizza Place

$s_1 =8.6$ sample deviation for Prim's

$s_2 =5.7$ sample deviation for Pizza Palca

$n_1 =n_2 = 100$ sample size selected for each case

The confidence interval for the difference of means is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

And for the 95% confidence we need a significance level of $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ , the degrees of freedom are given by:

$df= n_1 +n_2 -2= 100+100-2 =98$

And the critical value would be

$t_{\alpha/2}= 1.984$

And replacing we got:

$(240-210) -1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=27.953$

$(240-210) +1.984 \sqrt{\frac{8.6^2}{100}+\frac{5.7^2}{100}}=32.047$

And the confidence interval for the difference is between:

$27.953 \leq \mu_1 -\mu_2 \leq 32.047$

8 0

2 years ago

Sophie did an anyonymous survey and collected her friends' credit scores. the scores she found are listed in the table below. wh

MrRissso [65]

To find the mean of the data, you will combine all values together and then spread them all out evenly to create one value that represents the data.

In math this involves adding the data together and then dividing the sum by how many pieces of data there are.

682 + 601 + 744 + 674 + 701 + 790 + 676 + 638 + 773 = 6279

6279/9 = 697.66...

The rounded credit score is 698 (Choice A).

8 0

2 years ago

Read 2 more answers