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solniwko [45]
2 years ago
10

19% of a certain population of students at Hardy-Weinberg equilibrium is affected by an autosomal dominant condition called ‘laz

ybuttness’, which causes them to skip important lectures. What is the frequency of the students not affected with the ‘lazybuttness' in this population?
Mathematics
1 answer:
bazaltina [42]2 years ago
3 0

Answer:

81%

Step-by-step explanation:

Let 'L' be the dominant and 'l' e the recessive allele for ‘lazybuttness’.

Since ‘lazybuttness’ is an autosomal dominant condition, the 19% of students affected by the condition correspond to the  homozygous dominant (LL) and heterozygous (Ll) genotypes. Therefore, the rest of the population has the homozygous recessive genotype (ll) and is not affected. The frequency of students not affected is:

F = 100% - 19% = 81%

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Jenny paid $8.54 for pizza.she now has $16.79.with how much money did she start
otez555 [7]

Answer:

$25.33

Step-by step explanation:

In the start she had $8.54 + $16.79= $25.33

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A broker has a four-year contract to manage a rental unit for an investor. He is to receive 50% of the first month's rent and 5%
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Answer:

Step-by-step explanation:

600 X .50 = 300.00 1st month

600 X .05 = 30.00 47 months

30 X 47 = 1,410

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According to an informal poll in Glenview 1/3
Talja [164]

Answer:

Percent form: 41.65%

Fraction form: \frac{833}{2000}

Step-by-step explanation:

33% of men support John Smith.

67% of women support John Smith.

Lets say, for instance, that there are 20 polled individuals -- 10 women and 10 men.

However, since 1.5 times as many men voted as women, we have to apply our poll to 15 men and 5 women.

33% of the 15 men makes 5 men who voted for Smith and 10 who did not.

67% of the 5 women makes 3.33 women who voted for Smith and 1.67 who did not.

Add these numbers together.

8.33 total voters were cast for John Smith, while 11.67 were not.

Now, divide 8.33 by 20 and multiply by 100 to obtain a percentage.

\frac{8.33}{20} \\.4165\\41.65

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7 0
2 years ago
In a particular city, 82% of the residents have a desktop computer, 47% have a desktop computer and a laptop computer, and 3% ha
vagabundo [1.1K]

Answer:

B) 0.57

Step-by-step explanation:

Let's define:

  • A: the home has a laptop
  • B: the home has a desktop computer.

Data

  • P(B) = 0.82
  • P(A∩B) = 0.47

We want to find the probability that a home has a laptop given that it has a  desktop computer, that is, P(A|B).

P(A|B) = P(A∩B)/P(B) = 0.47/0.82 = 0.57

3 0
2 years ago
If a 40,000g cannon ball is 35m above the Earth’s surface, how much potential energy does the cannon ball have?
ELEN [110]

Answer:

Step-by-step explanation:

Remark

You could do this by converting the distance but the much more common way is to use kg and m.

Formula

PE = m * g * h

Givens

m = 40000 grams

m = 40000 grams * 1kg/1000 grams = 40 kg

g = 9.81

h = 35 m

Solution

PE = 40 * 9.81 * 35

PE = 13734 Joules

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2 years ago
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