First, divide the original measurements with the scaled ones. You'll get the same answer meaning that is the scale used by the model.
1500 ft. ÷7.5 ft = 200
600 ft. ÷ 3 ft. = 200
To simply check, if you divide 1500 with 200, the answer is 7.5 and 600 divided by 200 is 3.
To find the scaled dimension of the tennis court with actual dimension of 120 ft by 60 ft, divide both values with the scale used in the model which is 200.
120 ft. ÷ 200 = 0.6 ft
60 ft. ÷ 200 = 0.3 ft
The dimension of the tennis court in the scaled model is 0.6 ft long and 0.3 ft. wide.
Answer:
In February, 423 daytime minutes is used
Step-by-step explanation:
Let the base plan charges be x
And cost per daytime minute be y
In December,
x + 510y = 92.25------------------(1)
In January,
x + 397y = 77.56---------------------(2)
Subtracting eq(2) from eq(1)
x + 510y = 92.25
x + 397y = 77.56
-------------------------------
0 + 113y = 14.69
-------------------------------
y = \frac{14.69}{113}
y = 0.13----------------------------------(3)
Substituting (3) in (1)
x + 510(0.13) = 92.25
x + 66.3 = 92.25
x = 92.25 - 66.3
x = 25.95
So In February
base plan + (daytime minute)(cost per daytime minute) = 80.9
25.95 + (daytime minute)(0.13) = 80.9
(daytime minute)(0.13) = 80.9 - 25.95
(daytime minute)(0.13) = 54.95
(daytime minute) =
daytime minutes = 422.69
daytime minute 
Answer:
74613
Step-by-step explanation:
22C6 = 74613
Answer: option d.
Step-by-step explanation:
You have the following formul given in the problem:

You know that:
The number of customers serviced in an hour by the technical support representative is 6 costumbers, therefore:

As the problem asked for the probability that a costumber will be on hold less than 30 minutes, we know that:

Substitute the values above into the formula.
Then, you obtain:
or 95%
She scored better with math