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koban [17]
2 years ago
11

(1 point) Since 1966, 45% of the No. 1 draftpicks in the NBA have been centers. identify the population A. all No.1 draftpick ce

nters in the NBA since 1966 B. all NBA players since 1966 C. all No.1 draftpicks in the NBA since 1966 D. None of the above identify the specified attribute A. being a No.1 draftpicks in the NBA B. being an NBA player C. being a center D. None of the above is the proportion 0.45 (45%) a population proportion or a sample proportion? A. population proportion B. sample proportion C. None of the above​
Mathematics
1 answer:
Firdavs [7]2 years ago
6 0

Answer:

1 B

2 A

3 B

Step-by-step explanation:

1

The population is the total sample from which part of the event is considered. It's like in a set, the population would encompass everything as a whole. From the statement given, we're expected to find the population. The population is B.

All NBA players since 1966. This is because it is from this pool that the draft picks were selected, and narrowed down to 45% which were centre backs.

2

The specified attribute is A.

Being a No. 1 draft pick, because that's the fulcrum of the statement in itself

3

B sample proportion. The population like I stated above, is all NBA players since 1966, thus, a population proportion would have had the statement like this.

45% of all NBA players since 1966...

So, therefore, it's a sample proportion since it is referring to the draft pick, and not the NBA players

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Which fraction represents the decimal 0. ModifyingAbove 1 2 with Bar?
Licemer1 [7]

Answer:

\frac{3}{25}

Step-by-step explanation:

Given that \overline{0.12} is the repeating decimal.

The repeating decimal \overline{0.12} is converted into the fraction as :

\overline{0.12} = \frac{3}{x}

<=> 0.121212 = \frac{3}{x}

Multiplying both sides by x, we have,

<=> 0.121212x = 3

Dividing both sides by 0.121212, we get:

<=> x = \frac{3}{0.121212}

<=> x = 25

So the  fraction represents the decimal \overline{0.12} is: \frac{3}{25}

Hope it well find you well.

6 0
2 years ago
Read 2 more answers
Elaine is in London for one day only. She only has time to see two shows of the three shows she likes. The shows are Hamilton, A
denis-greek [22]

Answer:

\frac 13

Step-by-step explanation:

All three shows she likes are Hamilton, Aladdin, and Thriller.

But she can watch only two shows among the three shown.

The possible combination of the shows she can watch are

(Hamilton and Aladdin), (Aladdin and Thriller) and (Hamilton and Thriller).

So, the total number of possible events (available options)= 3.

As we have to determine the probability of watching Aladdin and Thriller, so here Aladdin and Thriller is the favorable event.

So, the number of favorable event=1

Now,

\text{Probability}=\frac{\text{Total number of possible events}}{\text{Total number of favorable events}}

=\frac{1}{3}

Hence, the probability that she sees Aladdin and Thriller is \frac 1 3.

5 0
2 years ago
The Patel family went apple picking. The number of red apples they picked was 2 __ 2 9 times the number of green apples they pic
miskamm [114]

Answer:

100

I first made 45 a fraction = 45/1

Then i made 2 2/9 into an improper fraction

then make my equation

45/1 ×20/9=100

answer is 100 red apples

Step-by-step explanation:

6 0
2 years ago
Which statements about the box plot are correct? Check all that apply.
Rudiy27

Answer:

The correct options are 1 and 3.

Step-by-step explanation:

From the given box plot it is clear that

\text{Minimum values}=34

Q_1=42

Q₁ is 25% of a data.

Median=46

Median is 50% of a data.

Q_3=70

Q₃ is 75% of a data.

\text{Maximum values}=76

34 is minimum value of the data and 46 is median it means 50% of the data values lies between 34 and 46. Therefore option 1 is correct.

42 is first quartile and and 70 is third quartile. it means 50% of the data values lies between 42 and 70. Therefore option 2 is incorrect.

The difference between Minimum value and first quartile, Maximum value and third quartile is less than 1.5×(IQR), therefore it is unlikely to have any outliers in the data.

Hence option 3 is correct.

The interquartile range of the data is

IQR=Q_3-Q_1

IQR=70-42=28

The interquartile range is 28. Therefore option 4 is incorrect.

Range of the data is

Range=Maximum-Minimum

Range=76-34=42

The range is 42. Therefore option 5 is incorrect.

3 0
2 years ago
Read 2 more answers
You are testing the claim that the mean GPA of night students is different from the mean GPA of day students. You sample 30 nigh
lorasvet [3.4K]

Answer:

Step-by-step explanation:

This is a test of 2 independent groups. The population standard deviations are not known. Let μ1 be the mean GPA of night students and μ2 be the mean GPA of day students.

The random variable is μ1 - μ2 = difference in the mean GPA of night students and the mean GPA of day students.

We would set up the hypothesis.

The null hypothesis is

H0 : μ1 = μ2 H0 : μ1 - μ2 = 0

The alternative hypothesis is

H1 : μ1 ≠ μ2 H1 : μ1 - μ2 ≠ 0

Since sample standard deviation is known, we would determine the test statistic by using the t test. The formula is

(x1 - x2)/√(s1²/n1 + s2²/n2)

From the information given,

x1 = 2.35

x2 = 2.58

s1 = 0.46

s2 = 0.47

n1 = 30

n2 = 25

t = (2.35 - 2.58)/√(0.46²/30 + 0.47²/25)

t = - 1.82

The formula for determining the degree of freedom is

df = [s1²/n1 + s2²/n2]²/(1/n1 - 1)(s1²/n1)² + (1/n2 - 1)(s2²/n2)²

df = [0.46²/30 + 0.47²/25]²/[(1/30 - 1)(0.46²/30)² + (1/25 - 1)(0.47²/25)²] = 0.00025247091/0.00000496862

df = 51

We would determine the probability value from the t test calculator. It becomes

p value = 0.075

Alpha = 5% = 0.05

Since alpha, 0.05 < than the p value, 0.075, then we would fail to reject the null hypothesis.

4 0
2 years ago
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