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Alisiya [41]
2 years ago
5

Find the sum and express it in scientific notation. 0.00348 + (6.2 x 10-2)

Mathematics
2 answers:
dybincka [34]2 years ago
6 0
0.00348+ (6.2 x 10-2)
0.00348+(6.2 x 8)
0.00349+(49.6)
=49.60348
dusya [7]2 years ago
3 0
0.00348 + (6.2 * 10^-2) =
0.00348 + 0.062 =
0.06548 =
6.548 * 10^-2 <=
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B is the midpoint of line segment AC

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if Amanda hikes at an average speed of 2.72 miles per hour, how long will it take her to hike 6.8 miles
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Which statements are true regarding triangle LMN? Check all that apply.
dimaraw [331]

Answer:

NM = x

LM = x\sqrt{2}

tan (45) = 1

Step-by-step explanation:

Step 1: Pythagoras Theorem

Pythagoras theorem relates the three sides of the triangle in such a way that the sum of the square of base and perpendicular is equal to hypotenuse, such as:

                                        LM^{2} =LN^{2} +NM^{2}

Step 2: Trigonometric Functions

Only for a right angle triangle following three trigonometric relations are valid

                                        sin (\theta) = \frac{opposite}{hypotenuse}

                                        cos (\theta) = \frac{adjacent}{hypotenuse}

                                    tan (\theta)=\frac{sin (\theta)}{cos (\theta)} = \frac{opposite}{adjacent}

Step 3: Verifying all the possible answers

A: Since, LN = x and using tan (45) =1

we can calculate

                                              tan (\theta)= \frac{opposite}{adjacent}

                                           tan (45)= \frac{NM}{x} =1

therefore, NM = x (true)

B: As NM = x therefore it can not be equal to x\sqrt{2\\}.

C: Using Pythagoras Theorem

                                        LM^{2} =LN^{2} +NM^{2}

                                           LM^{2} =x^{2} +x^{2}

                                              LM^{2} =2x^{2}

                                         LM = \sqrt{2x^{2}} = x\sqrt{2}

It can also be proved using trigonometric relation

                                           cos (45) = \frac{x}{LM}

                                            LM = \frac{x}{cos (45)}

As, \frac{1}{cos (45)}= \sqrt{2}

Therefore

                                            LM = x\sqrt{2}

D and E:

Using same approach similar to part A

Since, LN = x and NM = x

we can calculate

                                              tan (\theta)= \frac{opposite}{adjacent}

                                           tan (45)= \frac{x}{x} =1

Therefore, tan (45) = 1  and not equal to \frac{\sqrt{2} }{2}

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