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Harrizon [31]
2 years ago
13

After riding her bike for 20 miles. Angela got off and walked her bike the rest of the way at 5 miles per hour. If the total tri

p was 70 miles and took a total of 5 hours, how far did she ride and how far did she walk?
Mathematics
1 answer:
mylen [45]2 years ago
7 0

Answer:

She rode her bike 20 miles... I believe this may be a trick question.

Step-by-step explanation:

Let's break down this problem...

If she is going at a rate of 5 miles per hour while walking than the maximum she could have walked in 5 hours is 25 miles.

If Angela rode her bike for 20 miles, and the got off her bike and walked "<em>the rest of the way</em>" then she should have walked 50 miles. However as we already know her rate is 5 miles per hour while walking, and therefore could only have covered half that distance in 5 hours.

Is this a multiple choice question? Is there any misssing informaation?

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$290, 12.5%, 6 months
Veronika [31]
The information shown here only shows a principal sum, a rate of interest and a period or time. There is no question as to what is needed. But suppose the need is for simple interest, then we calculate using the given information and the formula: I = PRT where I is simple interest, P is the principal, R is the rate per year, and T is time P = 290, T is 6 months which is 0.5 years, R = 12.5 % which is written as 0.125 in decimal fraction. I = 290 × 0.125 x 0.5 → I = 18.125 Therefore after 6 months , the interest earned will be 18. 125 dollars
3 0
2 years ago
The national average for mathematics SATs in 2011 was 514 and the standard deviation was approximately 40. a) Within what bounda
blondinia [14]

Answer:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

Step-by-step explanation:

We don't know the distribution for the scores. But we know the following properties:

\mu = 514 , \sigma =40

For this case we can use the Chebysev theorem who states that "At least 1 -\frac{1}{k^2} of the values lies between \mu -k\sigma and \mu +k\sigma"

And we need the boundaries on which we expect at least 75% of the scores. If we use the Chebysev rule we have this:

0.75 = 1-\frac{1}{k^2}

If we solve for k we can do this:

\frac{1}{k^2}= 1-0.75=0.25

\frac{1}{0.25}= k^2

k^2 =4

k =\pm 2

So then we have at last 75% of the data withitn two deviations from the mean so the limits are:

Lower = \mu -2\sigma = 514- 2*40=434

Upper = \mu +2\sigma = 514 + 2*40=594

4 0
2 years ago
A proper unbiased coin was tossed 10 times for 3 trials, giving TTHHTHTTHH, TTTTTHHHHH, and THTHHHTTHT (T = Tails; H = Heads). W
Rashid [163]
Theoretical is what you think will be the outcome vs. actually doing it...hope this helps
3 0
2 years ago
Read 2 more answers
A researcher is using a repeated-measures design to test for mean differences among four treatment conditions. If the data for t
vodka [1.7K]

Answer:

Step-by-step explanation:

Given that a  researcher is using a repeated-measures design to test for mean differences among four treatment conditions.

The data for this study consist of 10 scores in each treatment.

We have to find the total subjects who participated in the study.

Each treatment has 10 scores

No of treatments = 4

Hence subjects participated in the study

= no of treatment x no of subjects

= 10*4=40

6 0
2 years ago
1) A 1.5 kg apple pie is sitting on the kitchen counter . If it has 13.44 J of gravitational potential energy, how tall is the c
vampirchik [111]

a)

Answer: 0.91 m

Explanation:

We know that,

P.E. = m g h

Where,

P.E = Potential energy

m = Mass of the object

g = acceleration due to gravity (9.8 m/s²)

It is given that, m = 1.5 kg

P.E. = 13.44 J

⇒ 13.44 = 1.5 kg × 9.8 m/s² × h

⇒ h = 0.91 m

Hence, apple sits om 0.91 m tall counter.

b)

Answer: 216 J

Explanation:

P.E. = m g h

Weight, mg = 120 N ( given)

height, h = 1.8 m ( given)

The energy possessed by the suitcase is due to virtue of its position (gravitational potential energy)

P.E. = 120 N × 1.8 m = 216 J

Hence, the energy possessed by the suitcase sitting on the counter is 216 J.

8 0
2 years ago
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