Answer:
• Because the sets are not symmetrical, the IQR should be used to compare the data sets.
• Because the sets contain outliers, the median should be used to compare the data sets.
• The mean and mode cannot be accurately determined based on the type of data display.
Step-by-step explanation:
When we observe the set of given data above, we can denote that the data obtained by comparing the height of students from class 1 and class 2 would not be similar hence we can say this obtained data is not symmetrical.
Due to the fact that this data is is obtained from different classes it is certain that there would be variations in the data when measuring the heights of the students and an error may occurs. These variations are referred to as OUTLIERS.
Therefore, Median or Interquartile range is the appropriate measure to be used for comparing the data sets.
Chance of winning $100 = 1/1000
<span>chance of winning $50 = 5/1000 = 1/200 </span>
<span>cost of ticket = -1 </span>
<span>E[x] = 100* 1/1000 + 50* 1/200 -1 </span>
<span>= 0.1 + 0.25 - 1 = -0.65
Hope this helps</span>
The actual quotient will be greater than 10 because 60 divided by 5 is 12, so the answer will be between 10 and 12, so it will be greater than 10
<span>measure of ∠EGF = 1/2( 180 - 50)
= 1/2(130)
= 65
</span><span>the measure of ∠CGF = 180 - 65
= 115</span>
