The answer would be letter B
Answer:
Quadrant I and III
Step-by-step explanation:
The coordinate (3,9) is all positive, therefore it lies in quadrant I.
The coordinate (-3,-9) is all negative, therefore it lies in quadrant III.
Answer:
The score of 271.2 on a test for which xbar = 240 and s = 24 has a higher relative position than a score of 63.6 on a test for which xbar = 60 and s = 6.
Step-by-step explanation:
Standardized score, z = (x - xbar)/s
xbar = mean, s = standard deviation.
For the first test, x = 271.2, xbar = 240, s = 24
z = (271.2 - 240)/24 = 1.3
For the second test, x = 63.6, xbar = 60, s = 6
z = (63.6 - 60)/6 = 0.6
The standardized score for the first test is more than double of the second test, hence, the score from the first test has the higher relative position.
Hope this Helps!!!
So the given series is "16, 06, 68, 88, __"
Count all the cyclical opening in each of these numbers. For example in 16, there is a one cyclical loop present in it(the one in 6), similarly in 06 it is two(one in zero and one in 6), going ahead, in 68 it is 3(one in 6 and two in 8).
From here on things become simple: hence, the cyclical figures in these equations written down becomes 1,2,3,4,_,3.
Let's now try solving the above sequence, going by the logical reasoning the only number that can fill in the gap should be 4.
The Set Up:
x² = (Side1)² + (Side2)² - 2[(Side1)(Side2)]
Solution:
cos(Toby's Angle) • x² = 55² + 65² - 2[(55)(65)] cos(110°)
x² = 3025 + 4225 -7150[cos(110°)]
x² = 7250 - 2445.44x =
√4804.56x = 69.31m
The distance, x, between two landmarks is 69.31m.
Note: The answer choices given are incorrect.
