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Nadusha1986 [10]
2 years ago
8

Two sandboxes with the same area are shown. The equation w(3w+1)=5^2 represents the area of Sandbox 2 in terms of its width. Whi

ch is the approximate length of the longest side of Sandbox 2? Round the answer to the nearest hundredth of a meter.
A.) 2.72 meters

B.) 3.06 meters

C.) 9.16 meters

D.) 10.18 meters

Mathematics
2 answers:
liubo4ka [24]2 years ago
6 0

sandbox 1 area = 5*5 = 25 square m

sandbox 2

25=w*(3w+1)=

3w^2+w-25=0

w=2.7248 (round to 2.72 m)

2.72*3=8.16+1 = 9.16

Longest side = 9.16 meters

gavmur [86]2 years ago
3 0

Answer:

C.) 9.16 meters

Step-by-step explanation:

We are given that the two sandboxes have same area and the equation is given by 25 = w*(3w+1).

Now, we simplify this equation in order to find the value of unknown variable 'w'.

i.e. 25 = 3w^{2}+w

i.e. 3w^{2}+w-25=0

The two factors of this quadratic equation are w=2.72 and w= -3.05.

But, as 'w' represents the length of the box, so it cannot be negative.

Therefore, w = 2.72

So, the longest side of the box is (3w+1) = 3*2.72+1 = 9.16 meter

Hence, the length of longest side to the nearest hundredth is 9.16 meter.


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Top 5% is 5.84 milliters and the bottom 5% is 5.60 millimeters.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

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X when Z has a pvalue of 0.95. So X when Z = 1.645

Z = \frac{X - \mu}{\sigma}

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Bottom 5%:

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