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Butoxors [25]
2 years ago
7

plssssssssssssssssssssss help Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no g

irl sits on either first or last chair. How many such arrangements are possible?
Mathematics
2 answers:
Airida [17]2 years ago
7 0

Answer:

672 ways

Step-by-step explanation:

The total number of ways the friends were supposed to sit without restrictions would have been = 6!

= 720 possible ways.

If the girs should sit on the first or last sit

The possible arrangement= 2!4!

= 2*24

= 48

But now the two girls should be arranged in such a way that the don't sit on either the first or the last chair.

So the possible way now is= way without restriction - way if the girls are to sit at either first or last sit

= 720-48

= 672

tatyana61 [14]2 years ago
5 0

Answer:

672.

Step-by-step explanation:

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The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced
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Answer:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.86,0.13)  

Where \mu=5.86 and \sigma=0.13

We are interested on this probability

P(5.5

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(5.5

And we can find this probability using the normal standard distribution or excel and we got:

P(-2.769

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2 years ago
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