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Tresset [83]
2 years ago
11

Scientists discover two planets orbiting a distant star. The average distance from the star to Planet A is 4 AU, and it takes 43

2 Earth days for Planet A to orbit the star. If it takes 1,460 days for Planet B to complete an orbit, what is the average distance from Planet B to the star?
A. 6 AU
B. 8 AU
C. 9 AU
D. 13.5 AU
Mathematics
1 answer:
Kitty [74]2 years ago
5 0

Answer:

Option C - 9 AU

Step-by-step explanation:

To find : What is the average distance from Planet B to the star?

Solution :

According to kepler's law,

The squares of the sidereal periods (of revolution) of the planets are directly proportional to the cubes of their mean distances from the Sun.

i.e. P^2\propto S^3

We have given,

The average distance from the star to Planet A is S_1=4 AU.

It takes 432 Earth days for Planet A to orbit the star i.e. P_1=432

It takes 1,460 days for Planet B to complete an orbit i.e.  P_2=1460

Substitute the values in (\frac{P_1}{P_2})^2=(\frac{S_1}{S_2})^3

(\frac{432}{1460})^2=(\frac{4}{S_2})^3

0.0875=(\frac{4}{S_2})^3

Taking root cube both side,

\sqrt[3]{0.0875}=\frac{4}{S_2}

0.444=\frac{4}{S_2}

S_2=\frac{4}{0.444}

S_2=9.00

The average distance from Planet B to the star is 9 AU.

Therefore, Option C is correct.

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Steve is buying a sandwich for lunch and some fresh fruit juice for his friends. The sandwich costs $3.92 and the fruit juice co
Svetradugi [14.3K]

Answer:

D

Step-by-step explanation

2+2-4

4 0
2 years ago
Jones of Boston borrowed $40,000, on a 90-day 10% note. After 60 days, Jones made an initial payment of $6,000. On day 80, Jones
MaRussiya [10]

Answer:

$34,666.67

Step-by-step explanation:

Step 1: Calculate the interest for 60 days.

(40000*60/360 )* 0.10 = $666.67

Step 2: Amount = Principal + Interest = $40,000 + 666.67 = $40,666.67

Step 3 : After 60 days, he paid $6000.

Remaining balance of the first payment = 40666.67 - 6000 = $34,666.67

Thank you.

8 0
1 year ago
In a group of 100 students, 25 own a laptop, 40 own a mobile phone, and 35 own either a
Talja [164]

Answer:

My best answer is that the probability is 35/100 that the student chosen at random owns neither a laptop nor a mobile phone.

Step-by-step explanation:

If you go back and read the introductory passage, you will notice it says, "In a group of 100 students... 35 own either a laptop or a mobile phone, but not both." And I think the other numbers, I.E. 25 and 40, were just meant to throw us off. Therefore, I think 35/100 is the probability.

8 0
2 years ago
What are the factors of the polynomial function? Use the rational root theorem to determine the factors. f(x) = 2x³ + x² - 8x -
fredd [130]

Answer:

( x + 2 ) ( x - 2 ) ( 2x + 1)

Step-by-step explanation:

coefficient of x³ is 2 and denote it with q and denote -4 as p

the set of possible rational roots through rational theorem will be within ± (p/q)

now factors of -4 are ±(1,2,4) and factors of 2 are ± (1,2) the possible rational roots are ± ( 1/1, 1/2, 2/1, 2/2, 4/1, 4/2) which reduces to ± (1, 1/2, 2, 4)

substitute each of the value into the equation

f(x) = 2x³ + x² - 8x - 4 to the root ( that gives f(x) = 0)

the equation can be made easy writing it in reduced form

2x³ + x² - 8x - 4

(2x³ + x²) - (8x + 4)

x² (2x + 1) - 4 (2x + 1)

(x² - 4) (2x + 1)

( x + 2 ) ( x - 2) ( 2x + 1) are the factors which correspond to 2, -2, -1/2 roots

4 0
2 years ago
Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}

Dividing we get,

2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}

Adding, we have,

2 { h } 54 \text { min }=2.9 {h}

Thus, the total time taken by Joshua is 2.9 {h}

To determine the average speed we use the formula,

speed=\frac{distance}{time}

where distance=7250 and time=2.9

Hence, substituting the values we have,

speed=\frac{7250}{2.9}

Dividing, we get,

speed=2500

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0
2 years ago
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