Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim
1 answer:
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is
Dividing we get,
Adding, we have,
Thus, the total time taken by Joshua is
To determine the average speed we use the formula,
where and
Hence, substituting the values we have,
Dividing, we get,
Thus, the average speed of Joshua during that time is 2500 m/h.
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Answer
The function represents the car’s value after x years.
f(x) = 20,000(0.85)x
Reason
As given
Terrence buys a new car for $20,000.
The value of the car depreciates by 15% each year.
15 % is written in the decimal form
= 0.15
Thus
The decrease in the value of car is represented by = a (1 - r)× t
Where a is the original cost
r is the depreciates rate in decimal form
t is time in years.
Here a = $20000 ,r = 0.15 , t = x years
The value of car after x years = 20,000 (1 -0.15)x
= 20000(0.85)x
Therefore the the value of the car after x years is represented by f(x) = 20,000(0.85)x .
Answer:
To determine the number of real number solutions of as system of equations in which one equation is linear and the other is quadratic
1) Given that there are two variables, x and y as an example, we make y the subject of the equation of the linear equation and substitute the the expression for y in x into the quadratic equation
We simplify and check the number of real roots with the quadratic formula, for quadratic equations the form 0 = a·x² - b·x + c
Where b² > 4·a·c there are two possible solutions and when b² = 4·a·c equation there is only one solution.
Step-by-step explanation: