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1 year ago

14

To find the distance between (-2,-3) and (4,1), Peggy's teacher drew a diagram and marked blue lines to represent the legs of a

right triangle. Peggy then used 42 and 62 to find the distance represented by the red segment. What distance did she find ?
A) 52
B) 114
C) 20
D) 25

1 answer:

Igoryamba1 year ago

3 0

Answer:

Ik this is late but the answer is A

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Explain what you can tell just by comparing the symbols in a picture graph

IceJOKER [234]

The <em>correct answer</em> is:

What objects we're comparing.

Explanation:

In a picture graph, symbols are used to represent the data being displayed. For example, if we took a survey on the types of foods people preferred at a cookout, we could use a picture of a hamburger, a picture of a hot dot and a picture of a chicken leg.

We cannot tell anything about the amounts in the graphs just by comparing the symbols.

5 0

2 years ago

Read 2 more answers

Have you ever been frustrated because you could not get a container of some sort to release the last bit of its contents? The ar

snow_tiger [21]

Answer:

Yes. There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Step-by-step explanation:

The sample of the remaining toothpaste is: [.53, .65, .46, .50, .37].

This sample has a size n=5, a mean M=0.502 and standard deviation s=0.102.

$M=\dfrac{1}{5}\sum_{i=1}^{5}(0.53+0.65+0.46+0.5+0.37)\\\\\\ M=\dfrac{2.51}{5}=0.502$

$s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^{5}(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.53-(0.502))^2+...+(0.37-(0.502))^2]}\\\\\\s=\sqrt{\dfrac{1}{4}\cdot [(0.001)+(0.022)+(0.002)+(0)+(0.017)]}\\\\\\ s=\sqrt{\dfrac{0.04188}{4}}=\sqrt{0.01047}\\\\\\s=0.102$

The 10% of the advertised content is:

$0.10\cdot 6.0\;oz=0.6\:oz$

Hypothesis test for the population mean:

The claim is that the remaining toothpaste is significantly is less than 10% of the advertised net content.

Then, the null and alternative hypothesis are:

$H_0: \mu=0.6\\\\H_a:\mu< 0.6$

The significance level is 0.05.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.102}{\sqrt{5}}=0.046$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{0.502-0.6}{0.046}=\dfrac{-0.098}{0.046}=-2.148$

The degrees of freedom for this sample size are:

$df=n-1=5-1=4$

This test is a left-tailed test, with 4 degrees of freedom and t=-2.148, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.049) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the remaining toothpaste is significantly is less than 10% of the advertised net content.

7 0

2 years ago

Christopher wrote the number pattern below.The first term is 8. 8,6,8,7,10

Aneli [31]

8 goes to 6 that’s -2 then goes back to 8 then goes to 7 that’s -1 add -1 and -2 and you get -3 but you add it like before so it’s 7 to 10 so then it’s 10 -4 to 6 then goes back to 10 to where you add 4 to get 14

4 0

1 year ago

Find the value of x, & y.<br> 3x-y+8x-7=x+2y+5x+3y

Advocard [28]

Please rewrite this equation(s) using parantheses than needed

thank you

5 0

1 year ago

Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10

Alborosie

Answer:

<em>The probability is 42%</em>

Step-by-step explanation:

<u>Conditional Probability</u>

It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).

If P(A) is the probability of occurrence of A, $P(A\cap B)$ is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:

$\displaystyle P(B|A)=\frac{P(A\cap B)}{P(A)}$

We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.

The probability that a randomly selected band member plays the trumpet is

$\displaystyle P(A)=\frac{24}{125}$

The probability that he or she has both attributes is

$\displaystyle P(A\cap B)=\frac{10}{125}$

Thus, the required conditional probability is

$\displaystyle P(B|A)=\frac{\frac{10}{125}}{\frac{24}{125}}$

$\displaystyle P(B|A)=\frac{10}{24}=\frac{5}{12}=0.42$

The probability is 42%

5 0

2 years ago