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Crazy boy [7]
2 years ago
12

a dart board has 10 equally sized slices numbered from 1-10. some are grey and some are white. the slices numbered 1,2,3,4,5,6,8

,9 and 10 are grey. the slice number 7 is white. a dart is tossed and lands on a slice at random. let X be the event that the dart lands on a grey slice, and let P(X) be the probability of x. let not X be the event that the dart lands on a slice that is not grey,and let P( not X) be the probability of not X.
Mathematics
1 answer:
mr_godi [17]2 years ago
6 0

Answer:

We have 10 sections, we can assume that the probability of hitting each of one of them is the same.

we have 9 grey slices and 1 white slice, then the probability of landing in a grey slice is equal to the number of grey slices divided by the total number of slices:

P(X) = 9/10 = 0.90

The probability of not landing in a grey slice is equal to the probability of landing in the white slice, this is:

P(not X) = 1/10 = 0.10

Also, when you have only two events, you can calculate this as:

P(not X) = 1 - P(X) = 1 - 0.90 = 0.10

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A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long. What is the length of the
lukranit [14]

Answer:

The length of the remaining piece of thread is  \frac{1}{16}.

Step-by-step explanation:

Given:

A tailor cuts a piece of thread One-half of an inch long from a piece Nine-sixteenths of an inch long.

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Total thread  = \frac{9}{16} \ inch.

Tailor cuts a piece of thread = \frac{1}{2}\ inch.  

Now, to get the length of the remaining piece of thread by subtracting tailor cuts a piece of thread from the total thread:

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Therefore, the length of the remaining piece of thread is  \frac{1}{16}.

8 0
1 year ago
Figure ABCD is transformed to obtain figure A'B'C'D': A coordinate grid is shown from negative 6 to 6 on both axes at increments
nika2105 [10]

Given:

Vertices of ABCD are A(-4,4), (-2,2), C(-2,-1) and D(-4,1).

Vertices of A'B'C'D' are A'(3,-4), B'(5,-2), C'(5,1) and D'(3,-1).

To find:

The sequence of transformations that changes figure ABCD to figure A'B'C'D'.

Solution:

Part A:

The figure ABCD reflected across the x-axis, then

(x,y)\to (x,-y)

Using this rule, we get

A(-4,4)\to A_1(-4,-4)

Similarly, the other points are B_1(-2,-2),C_1(-2,1),D_1(-4,-1).

Then figure translated 7 units right to get A'B'C'D'.

(x,y)\to (x+7,y)

A_1(-4,-4)\to A'(-4+7,-4)=A'(3,-4)

Similarly, the other points are B'(5,-2), C'(5,1),D'(3,-1).

Therefore, the figure ABCD reflected across the x-axis and then translated 7 units right to get A'B'C'D'.

Part B:

Reflection and translation are rigid transformation, it means shape and size of figures remains same after reflection and translation.

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8 0
2 years ago
Tickets to a musical cost $30 for adults and $12 for children. At one particular performance 960 people attended and $19 080 was
postnew [5]
In order to solve this, you have to set up a systems of linear equations.

Let's say that children = c and adults = a

30a + 12c = 19,080
a + c = 960

I'm going to show you how to solve this system of linear equations by substitution, the easiest way to solve in my opinion.

   a + c = 960 
       - c    -    c
 ---------------------- ⇒ Step 1: Solve for either a or c in either equation.
   a = 960 - c 



20(960 - c)+ 12c = 19,080
19,200 - 20c + 12c = 19,080
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 - 19,200         - 19,200
---------------------------------- ⇒ Step 2: Substitute in the value you got for a or c
         8c = -120                    into the opposite equation.                                                
       ------  ---------
          8         8
 
         c = -15



30a + 12(-15) = 19,080
   30a - 180 = 19,080
          + 180  +     180
 -------------------------------
   30a = 19,260
  -------   -----------
    30          30
     
       a = 642
__________________________________________________________

I just realized that there can't be a negative amount of children, so I'm sorry if these results are all wrong. 


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