Answer:
Step-by-step explanation:
step 1
Determine the slope of the dashed line
The formula to calculate the slope between two points is equal to
we have
(-3,1) and (0,3)
substitute
step 2
Find the equation of the dashed line in slope intercept form
we have
---> given problem
substitute
step 3
Find the equation of the inequality
we know that
Is a dashed line and everything to the left of the line is shaded
so
see the attached figure to better understand the problem
The Mean = (135 + 71 + 69 + 80 + 158 + 152 + 161 + 96 + 122 + 118 + 87 + 85 ) : 12 = 111.166
The smallest value : 69
The greatest value : 161
s² = ∑( x i - x )² / ( n - 1 )
s² = ( 568.274 + 1613.3 + 1777.97 + 971.32 + 2193.42 + 1667.4 + +2483.42 + 230 + 117.38 + 46.7 + 584 + 684.66 ) : 11
s² = 1176.1676
s = √s² = √1176.1676
s ( Standard deviation ) = 34.295
All the values fall within 2 standard deviations:
x (Mean) - 2 s and x + 2 s
100×6
6×90
6×8
add them together
community property
Answer:
The maximum amount of time is 48.2 minutes
Step-by-step explanation:
We can use the equation for a line
y = mx+b
the inital value is 75 gallons ( that is b)
the slope is 2.5 gallons (that is m)
We know that we want to fill it to 195.5 gallons ( that would be y)
195.5 = 2.5x +75
We are going to solve for x (that is the number of minutes)
Subtract 75 from each side
195.5-75 = 2.5x +75-75
120.5 = 2.5x
Divide by 2.5 on each side
120.5/2.5 = 2.5x/2.5
48.2 =x
The maximum amount of time is 48.2 minutes
(i) speed = distance / time
so time = distance / speed
here we have
time t = 1080/x hours
(ii) return flight time = 1080 / (x + 30) hours
(a) 1080/x - 1080/(x + 30) = 1/2
Multiplying through by the LCD 2x(x + 30) we get:-
1080*2(x + 30) - 2x*1080 = x(x+30)
2160x + 64800 - 2160x = x^2 + 30x
x^2 + 30x - 64800 = 0
(b) factoring; -64800 = 270 * -240 ans 270-240 = 30 so we have
(x + 270)(x - 240) = 0 so x = 240 ( we ignore the negative -270)
So the speed for outward journey is 240 km/hr
(c) time ffor outward flight = 1080 / 240 = 4 1/2 hours
(d) average speed for whole flight = distance / time
Time for outward journey = 4.5 hours and time for return journey = d / v
= 1080 / (240+30) = 4 hours
Therefore the average speed for whole journey = 2160 / 8.5 = 254.1 km/hr
