Name the value of each 2 in 222,222

2 answers:

8 0

the underlined 2 in 222,222 is in the hundred thousand place (two hundred thousand)

the underlined 2 in 222,222 is in the ten thousand place (twenty thousand)

the underlined 2 in 222,222 is in the thousand place (two thousand)

the underlined 2 in 222,222 is in the hundred place (two hundred)

the underlined 2 in 222,222 is in the ten place (twenty)

the underlined 2 in 222,222 is in the ones place (two)

kicyunya [14]2 years ago

3 0

it can be,

ones, tens, hundreds, thousands, ten thousands, hundred thousands

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How would the fraction 1/3+square root of 2 be rewritten if its denominator is rationalized using difference of squares? A. 3-sq

Vera_Pavlovna [14]

given 1 /( 3 + √2 )

then rationalise the denominator by multiplying the numerator/ denominator by the conjugate of the denominator

the conjugate of 3 + √2 is 3 - √2

1 / (3 + √2 ) × (3 - √2 ) / (3 - √2 )

= (3 - √2 ) /( 9 - 2 ) = (3 - √2 ) / 7

4 0

2 years ago

Read 2 more answers

Mike has coffee worth $4 per pound that he wishes to mix with 20 pounds of coffee worth $7 per pound to get a mixture that can b

Alinara [238K]

$\bf \begin{array}{lccclll}
&\stackrel{lbs}{amount}&\stackrel{per~lb}{price}&\stackrel{amount}{price}\\
&------&------&------\\
\textit{\$4/lb coffee}&x&4&4x\\
\textit{\$7/lb coffee}&20&7&140\\
------&------&------&------\\
mixture&y&5&5y
\end{array}$

so, we know the mixture is the sum of both types of coffee, thus x + 20 = y, and 4x + 140 = 5y.

$\bf \begin{cases}
x+20=\boxed{y}\\
4x+140=5y\\
----------\\
4x+140=5\left( \boxed{x+20} \right)
\end{cases}
\\\\\\
4x+140=5x+100\implies 140-100=5x-4x\implies 40=x$

5 0

2 years ago

True or false the ordered pair of x-intercept has a zero for the x-value

Artyom0805 [142]

X-intercept has coordinates (x,0)
Y-intercept has coordinates (0,y)
So, the statement " The ordered pair of x-intercept has a zero for the x-value" is false.
 The ordered pair of x-intercept has a zero for the y-value.

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A sample of 2,000 licensed drivers revealed the following number of speeding violations. Number of Violations Number of Drivers

Arturiano [62]

Answer:

The probability that a particular driver had exactly two speeding violations is 0.009.

Step-by-step explanation:

We are given that a sample of 2,000 licensed drivers revealed the following number of speeding violations;

Number of Violations Number of Drivers

0 1,910

1 46

2 18