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madam [21]
1 year ago
9

How would the fraction 1/3+square root of 2 be rewritten if its denominator is rationalized using difference of squares? A. 3-sq

uare root of 2 B. 3-square root of 2/5 C. 3-square root of 2/7 D. - 3+square root of 2/7
Mathematics
2 answers:
olga55 [171]1 year ago
8 0

Answer:

\frac{3-\sqrt{2} }{7}

is correct

Step-by-step explanation:

Vera_Pavlovna [14]1 year ago
4 0

C

given 1 /( 3 + √2 )

then rationalise the denominator by multiplying the numerator/ denominator by the conjugate of the denominator

the conjugate of 3 + √2 is 3 - √2

1 / (3 + √2 ) × (3 - √2 ) / (3 - √2 )

= (3 - √2 ) /( 9 - 2 ) = (3 - √2 ) / 7

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Of 100 students,65 are members of a mathematics club and 40 are members of a physics club. if 10 are members of neither club the
alexandr1967 [171]

a. 15 students are members of both clubs

b. 50 students only are members of the mathematics club

c. 25 students only are members of the physics club

Step-by-step explanation:

The given is:

  • There are 100 students
  • 65 are members of a mathematics club
  • 40 are members of a physics club
  • 10 are members of neither club

We need to find how many students are members of

a. both clubs?

b. only mathematics club

c. only physics club

∵ The total number of students = 100

∵ 10 are members of neither club

- Subtract 10 from 100 to find the members of the mathematics

  club or the physics club

∵ 100 - 10 = 90

∴ There are 90 members of the mathematics club or physics club

∴ n(mathematics or physics) = 90

∵ 65 students are members of a mathematics club

∵ n(mathematics) = 65

∵ 40 students are members of a physics club

∴ n(physics) = 40

∵ n(mathematics or physics) = n(mathematics) + n(physics) - n(both)

∴ 90 = 65 + 40 - n(both)

∴ 90 = 105 - n(both)

- Add n(both) to each side

∴ n(both) + 90 = 105

- Subtract 90 from each side

∴ n(both) = 15

∴ 15 students are members of both clubs

a. 15 students are members of both clubs

∵ 65 students are members of the mathematics club

∵ 15 of them are members of the physics club

∴ n(mathematics only) = 65 - 15 = 50

∴ 50 students only are members of the mathematics club

b. 50 students only are members of the mathematics club

∵ 40 students are members of the physics club

∵ 15 of them are members of the mathematics club

∴ n(physics only) = 40 - 15 = 25

∴ 25 students only are members of the physics club

c. 25 students only are members of the physics club

Learn more:

You can learn more about word problems in brainly.com/question/8907574

#LearnwithBrainly

5 0
2 years ago
At Central High School, there are 48 football players and 20 cheerleaders. What is the ratio of cheerleaders to football players
Ahat [919]

Answer:

5 : 12

Step-by-step explanation:

Cheerleaders : football players

20 : 48

5 : 12

6 0
2 years ago
Read 2 more answers
Point F is on circle C. What is the length of line segment GF? 12.5 units 15.0 units 17.5 units 20.0 units
geniusboy [140]
The answer:
According to the image, <span>the length of line segment GF can be found with
</span>GF= GC +CF
CF is one the radius, so CF=7.5
to find GC, we can apply Pythagorean theorem on the right triangle GEC
it is 
GC² =GE² + EC² = 10² +7.5² =156.25, and then GC= sqrt(156.25)=12.5

therefore, GF= GC +CF=12.5+7.5=20

so the answer is <span>20.0 units</span>
7 0
1 year ago
Before school, janine spends 1/10 hour making the bed, 1/5 hour getting dressed, and 1/2 hour eating breakfast. What fraction of
N76 [4]
4/5 of an hour spent
6 0
1 year ago
Circle two addends to add first find the sum explain your strategy 7+3+2
irga5000 [103]
7 plus 3 first than plus 2 my strategy is to look at the easier thing to add than add the second one
4 0
1 year ago
Read 2 more answers
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