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grin007 [14]
2 years ago
14

Andre ran 2 kilometers in 15 minutes, and Jada ran 3 kilometers in 20 minutes. Both ran at a constant speed. Did they run at the

same speed?
Mathematics
1 answer:
Goshia [24]2 years ago
6 0

Answer:

speed of Jada = 6km per hour which is not equal to

speed of Andre = 8km per hour

They did not run at same speed

Step-by-step explanation:

formula of speed = distance covered/ time taken

For Andre

Distance = 2 KM

time = 15 mins

60 mins = 1 hour

15 mins = 1/60 * 15 hour = 0.25 hours

thus,

speed = 2km/0.25 hour = 8 km per hour

Similarly for Jada

Distance = 3 KM

time = 20 mins

60 mins = 1 hour

20 mins = 1/60 * 20 hour = 1/3 hours

thus,

speed = 2km/(1/3)hour = 6  km per hour

Now we have

speed of Jada = 6km per hour which is not equal to

speed of Andre = 8km per hour

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Answer:

$1.00

Step-by-step explanation:

Total Budget = $35

Cake Spent = $18

Remaining Money = 35 - 18 = $17

Since, each balloon is worth $4, to find how many balloons he will get with remaining money ($17), we divide the the remaining money by price of each balloon:

17/4 = 4.25

We can't have fractional balloons, so Abit can get 4 balloons, MAXIMUM.

4 balloons cost = $4 per balloon * 4 = $16

So, from $17 if he spends $16 for balloons, he will have left:

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2 years ago
Employees in the marketing department of a large regional restaurant chain are researching the amount of money that households i
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Answer:

The <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

Step-by-step explanation:

The data provided is as follows:

25 to 34              45 to 54

  1329                    2268

  1906                    1965

 2426                     1149

  1826                     1591

  1239                    1682

   1514                     1851

  1937                     1367

  1454                    2158

Compute the mean and standard deviation for the group "25 to 34" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [1329+1906+...+1454]=\frac{13631}{8}=1703.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1086710.875}=394.01

Compute the <em>z</em>-score for the group "25 to 34" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1703.875}{394.01}=0.3734\approx 0.37

Compute the mean and standard deviation for the group "45 to 54" as follows:

\bar x=\frac{1}{n}\sum x=\frac{1}{8}\times [2268+1965+...+2158]=\frac{14031}{8}=1753.875\\\\s=\sqrt{\frac{1}{n-1}\sum (x-\bar x)^{2}}=\sqrt{\frac{1}{8-1}\times 1028888.875}=383.39

Compute the <em>z</em>-score for the group "45 to 54" as follows:

z=\frac{x-\bar x}{s}=\frac{1851-1753.875}{383.39}=0.25333\approx 0.25

Thus, the <em>z</em>-score for the group "25 to 34" is 0.37 and the <em>z</em>-score for the group "45 to 54" is 0.25.

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Answer:

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Step-by-step explanation:

The inequality describes the range of monthly average temperatures T in degrees Fahrenheit at a certain location.

The inequality expression is given as:

|T-43|\leq 22

now this expression could also be expressed as:

-22\leq T-43\leq22\\\\-22+43 \leq T \leq 22+43\\\\21\leq T\leq 65

Now if the high and low monthly average temperatures satisfy the inequality, then the , monthly averages are always within 22 degrees of 43°F.

( As the difference is 22 degrees to the left and right)

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Answer:

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A proportional relationship occurs only with a linear relationship that goes through the origin.

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