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ozzi
2 years ago
12

A company buys paper at the rate of $10.50 per package for the first 10 packages, $8.50 per package for the next 10 packages, an

d $5.50 per package for any additional packages. How many packages of paper can be bought for $322.00?
Mathematics
2 answers:
dexar [7]2 years ago
7 0

Answer:

25?

Step-by-step explanation:


spin [16.1K]2 years ago
6 0

Answer:

44

Step-by-step explanation:

10 (packages) * 10.5 = $105  

10 (packages) * 8.5 = $85

$105 + $85 = $190  

$322 - $190 = $132  

$132/$5.50 = 24 packages

So 20 (packages) + 24 (packages)  = 44

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A random sample of 6 homes in Gainesville, Florida between 1800 and 2200 square feet had a mean of 212990 and a standard deviati
Andrej [43]

Answer:

The 95% confidence interval for the average price of a home in Gainesville of this size is between 183,772.5 square feet and 242,207.5 square feet.

Step-by-step explanation:

We have the standard deviation of the sample, so we use the students t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 6 - 1 = 5

Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of 0.95(t_{95}). So we have T = 2.015

The margin of error is:

M = T*s = 2.015*14500 = 29217.5.

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 212990 - 29217.5 = 183,772.5 square feet

The upper end of the interval is the sample mean added to M. So it is 212990 + 29217.5 = 242,207.5 square feet

The 95% confidence interval for the average price of a home in Gainesville of this size is between 183,772.5 square feet and 242,207.5 square feet.

3 0
2 years ago
The Acme Candy Company claims that​ 60% of the jawbreakers it produces weigh more than 0.4 ounces. Suppose that 800 jawbreakers
vichka [17]

Answer:

Yes, it would be statistically significant

Step-by-step explanation:

The information given are;

The percentage of jawbreakers it produces that weigh more than 0.4 ounces = 60%

Number of jawbreakers in the sample, n = 800

The mean proportion of jawbreakers that weigh more than 0.4 = 60% = 0.6 = \mu _ {\hat p} =p

The formula for the standard deviation of a proportion is \sigma  _{\hat p} =\sqrt{\dfrac{p(1-p)}{n} }

Solving for the standard deviation gives;

\sigma  _{\hat p} =\sqrt{\dfrac{0.6 \cdot (1-0.6)}{800} } = 0.0173

Given that the mean proportion is 0.6, the expected value of jawbreakers that weigh more than 0.4  in the sample of 800 = 800*0.6 = 480

For statistical significance the difference from the mean = 2×\sigma _{\hat p} = 2*0.0173 = 0.0346 the equivalent number of Jaw breakers = 800*0.0346 = 27.7

The z-score of 494 jawbreakers is given as follows;

Z=\dfrac{x-\mu _{\hat p} }{\sigma _{\hat p}  }

Z=\dfrac{494-480 }{0.0173  } = 230.94

Therefore, the z-score more than 2 ×\sigma _{\hat p} which is significant.

8 0
2 years ago
If a 5 foot post casts an 8 foot shadow at the same time that a nearby tree casts a 48 foot shadow how tall is the tree
andriy [413]
The first thing we are going to assume for this case is that the tree and the post are located in the same place.
 From that place, both cast a shadow in the same direction.
 We then have two similar triangles.
 Therefore, we have the following relationship:
 \frac{x}{48} = \frac{5}{8}
 From here, we clear the value of x.
 We have then:
 x = \frac{5}{8} *48
 Rewriting:
 x=30
 Answer:
 
the tree is 30 feet tall
3 0
2 years ago
Suppose a population of 250 crickets double in size every 3 months how many crickets will there be after 2 years
Hitman42 [59]

if they double in size every 3 months and there are 12 months in a year, just multiply 250x4=1000 then multiply that by 2. 1000x2=2000

3 0
2 years ago
The manager of a shopping mall distributed a customer-satisfaction survey by handing it to people as they came through one of th
Nina [5.8K]

Answer:

No. The results of the survey cannot be generalized to the population of all customers of the shopping mall.

Step-by-step explanation:

Survey results are biased, because data is collected from customers who came trough one specific door of the mall.

Some of the customers <em>may be using some other door </em>where satisfaction survey is not given to these people while passing the door.

Therefore survey results does not reflect thoughts of the population of all customers.

4 0
2 years ago
Read 2 more answers
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