Which equations represent the data in the table? Check all that apply.
2 answers:
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Answer:
The probability of you winning is 1/3
No, it is not a fair game
Step-by-step explanation:
The first thing we need to have here is the sample space. This refers to the set of all possible results that can occur from the rolling.
Please check attachment for this
Kindly note that the total number of possible outcomes is 36.
And in the attachment, sums which are divisible by 3 are circled.
The number of circles we can count is 12
Thus, the probability of you winning would be number of circles/total number of outcomes = 12/36 = 1/3
Is it a fair game?
No, it is not
It can only be a fair game if the probability of winning equals probability of losing ( which is 18/36 = 1/2 or 0.5)
Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>Step-by-step explanation:
Given the function j(x) = 11.6 and k(x) =
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6 and k(x) =
are inverse functions.