Answer: 2.845
Step-by-step explanation:
The formula to find the standard deviation is given by :-
, where p is the probability of getting success in each trial and n is the sample size.
Given : Sample size : n=110
The proportion of employees older than 55 and considering retirement : p=0.08
Then, the standard deviation is given by :-

Hence, the standard deviation for the sampling distribution of the sample proportions is 2.845.
Oh dear~This can only be simplified。
15X+18y
3(5X+6Y)
That's your answer.
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Answer:
D sentence 5
Step-by-step explanation: