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Ulleksa [173]
2 years ago
12

Find three different surfaces that contain the curve r(t) = t^2 i + lnt j + (1/t)k

Mathematics
1 answer:
Viefleur [7K]2 years ago
7 0

solution:

Consider the curve: r(t) = t²i +(int)j + 1/t k

X= t² , y = int ,z = 1/t

Using, x = t², z = 1/t

                    X = (1/z)²

Xz²= 1

Using y = int, z= 1/t

Y = in│1/z│

Using x = t², y = int

Y = int

= in(√x)

Hence , the required surface are,

Xz² = 1

Y = in│1/z│

Y= in(√x)


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Alia wants to write the equation of the graphed line in point-slope form. These are the steps she plans to use:
baherus [9]
(2,5)(1,3)
slope(m) = (3 - 5) / (1 - 2) = -2/-1 = 2 (2 units up, one unit to the right)

y - y1 = m(x - x1)....using (1,3)
y - 3 = 2(x - 1)....talia's last step is incorrect because she didn't sub in her slope of 2
6 0
1 year ago
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A scientist who studies teenage behavior was interested in determining if teenagers spend more time playing computer games then
Marina86 [1]

Answer:

- The amount of time greater than 10.2 hours for this year.

- The P_{value} is 0.01358.

Step-by-step explanation:

Given information:

mean, X = 10.2 hours

sample, n = 15

using t distribution

test statistics = 2.822

P_{value} = 2 x P(t_{n-1} > test statistics)

                              = 2 x P(t_{15-1} > 2.822)

                              = 2 x 0.00679

                              = 0.01358

P_{value} is less than 0.10 which indicates that the amount of time greater than 10.2 hours for this year.

5 0
2 years ago
A circle with radius of \greenD{5\,\text{cm}}5cmstart color #1fab54, 5, start text, c, m, end text, end color #1fab54 sits insid
Marat540 [252]

Answer:

The area of the shaded region is 42.50 cm².

Step-by-step explanation:

Consider the figure below.

The radius of the circle is, <em>r</em> = 5 cm.

The sides of the rectangle are:

<em>l</em> = 11 cm

<em>b</em> = 11 cm.

Compute the area of the shaded region as follows:

Area of the shaded region = Area of rectangle - Area of circle

                                            =[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50

Thus, the area of the shaded region is 42.50 cm².

7 0
1 year ago
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Which of the following could be the ratio of the length of the longer leg of a 30-60-90 triangle to the length of its hypotenuse
Aliun [14]

Answer:

Option C is correct.

Ratio of longer leg to hypotenuse is;  \sqrt{3} : 2

Step-by-step explanation:

This is the special right angle triangle 30°-60°-90°  as shown below in the figure.

  • The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
  • The side opposite the 60° angle will be the longer leg, because 60 degrees is the mid-sized degree angle in this triangle.
  • Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.

In 30°−60°−90° right triangle,

  • the length of the hypotenuse is twice the length of the shorter leg,also
  • the length of the longer leg is \sqrt{3} times the length of the shorter leg.

Then:

the sides are in proportion i.e,  1:\sqrt{3} :2

Therefore, the ratio of the length of the longer leg to the length of its hypotenuse is:  \sqrt{3} : 2



7 0
2 years ago
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Raymond just got done jumping at Super Bounce Trampoline Center. The total cost of his session was \$43.25$43.25dollar sign, 43,
Elodia [21]

Answer:

29 minutes

Step-by-step explanation:

Given

Total = \$43.25

Entrance\ Fee = \$7

Per\ Minute = \$1.25

Required

Determine the number of minutes (t) that he was on the trampoline.

This can be expressed as:

Total\ Payment = Entrance\ Fee + Amount\ per\ minute * t

Where t represents the number of minutes

Substitute values for Total, Entrance Fee and Amount per minute

43.25 = 7 + 1.25 * t

43.25 = 7 + 1.25t

Solving further to get the value of t, we have:

1.25t = 43.25 - 7

1.25t = 36.25

t = 36.25/1.25

t = 29

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1 year ago
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