(2,5)(1,3)
slope(m) = (3 - 5) / (1 - 2) = -2/-1 = 2 (2 units up, one unit to the right)
y - y1 = m(x - x1)....using (1,3)
y - 3 = 2(x - 1)....talia's last step is incorrect because she didn't sub in her slope of 2
Answer:
- The amount of time greater than 10.2 hours for this year.
- The
is 0.01358.
Step-by-step explanation:
Given information:
mean, X = 10.2 hours
sample, n = 15
using t distribution
test statistics = 2.822
= 2 x P(
> test statistics)
= 2 x P(
> 2.822)
= 2 x 0.00679
= 0.01358
is less than 0.10 which indicates that the amount of time greater than 10.2 hours for this year.
Answer:
The area of the shaded region is 42.50 cm².
Step-by-step explanation:
Consider the figure below.
The radius of the circle is, <em>r</em> = 5 cm.
The sides of the rectangle are:
<em>l</em> = 11 cm
<em>b</em> = 11 cm.
Compute the area of the shaded region as follows:
Area of the shaded region = Area of rectangle - Area of circle
![=[l\times b]-[\pi r^{2}]\\\\=[11\times 11]-[3.14\times 5\times 5]\\\\=121-78.50\\\\=42.50](https://tex.z-dn.net/?f=%3D%5Bl%5Ctimes%20b%5D-%5B%5Cpi%20r%5E%7B2%7D%5D%5C%5C%5C%5C%3D%5B11%5Ctimes%2011%5D-%5B3.14%5Ctimes%205%5Ctimes%205%5D%5C%5C%5C%5C%3D121-78.50%5C%5C%5C%5C%3D42.50)
Thus, the area of the shaded region is 42.50 cm².
Answer:
Option C is correct.
Ratio of longer leg to hypotenuse is; 
Step-by-step explanation:
This is the special right angle triangle 30°-60°-90° as shown below in the figure.
- The side opposite the 30° angle is always the shortest because 30 degrees is the smallest angle.
- The side opposite the 60° angle will be the longer leg, because 60 degrees is the mid-sized degree angle in this triangle.
- Finally , the side opposite the 90° angle will always be the largest side(Hypotenuse) because 90 degrees is the largest angle.
In 30°−60°−90° right triangle,
- the length of the hypotenuse is twice the length of the shorter leg,also
- the length of the longer leg is
times the length of the shorter leg.
Then:
the sides are in proportion i.e, 
Therefore, the ratio of the length of the longer leg to the length of its hypotenuse is: 
Answer:
29 minutes
Step-by-step explanation:
Given



Required
Determine the number of minutes (t) that he was on the trampoline.
This can be expressed as:

Where t represents the number of minutes
Substitute values for Total, Entrance Fee and Amount per minute


Solving further to get the value of t, we have:



