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guajiro [1.7K]
2 years ago
14

Andrea has a yard shaped like parallelogram ABCD. The garden area, parallelogram EFGB, has an area of 105 ft2004-05-02-04-00_fil

es/i0170000.jpg. If Andrea wants to sod the rest of her yard, how many square feet of sod should she order?
Mathematics
1 answer:
Lynna [10]2 years ago
5 0

The area of a parallelogram is simply calculated using the formula:

A = b * h

Where,

b = length of the base = 45 ft

h = height which is perpendicular to the base = 21 ft

Using the formula, we calculate the total area of the yard.

A = b* h

A = 45 ft * 21 ft

A = 945 ft^2

Now we don’t want to sod the Garden area for the most obvious reason. The garden has an Area of 105 ft^2, we subtract this to the total area giving us,

Area to sod = 945 ft^2 – 105ft^2

<span>Area to sod = 840 ft^2</span>

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Pavel [41]

Answer:

a) For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

b) P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

c) P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

d) P(X \geq 1)= 1-P(X

And using the result from part a we got:

P(X \geq 1)= 1-P(X

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Binom(n p)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Part a

For this case we can use the binomial model since we assume independent events and the same probability for each trial is the same p =0.15

Part b

For this case we want this probability:

P(X=0)

And replacing we got:

P(X=0)=(10C0)(0.15)^0 (1-0.15)^{10-0}=0.1969

Part c

For this case we want this probability:

P(X=3)

And replacing we got:

P(X=3)=(10C3)(0.15)^3 (1-0.15)^{10-3}=0.1298

Part d

For this cae we want thi probability:

P(X \geq 1)

And we can use the complment rule and we got:

P(X \geq 1)= 1-P(X

And using the result from part a we got:

P(X \geq 1)= 1-P(X

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2 years ago
Let ​ f(x)=x2+5x−36 ​. Enter the x-intercepts of the quadratic function in the boxes.
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Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 

                     x^2-5*x-(36)=0 

Step by step solution:<span> Step 1:</span> Trying to factor by splitting the middle term

<span> 1.1 </span>    Factoring <span> x2-5x-36</span> 

The first term is, <span> <span>x2</span> </span> its coefficient is 1.
The middle term is, <span> -5x </span> its coefficient is  - 5.
The last term, "the constant", is <span> -36 </span>

Step-1: Multiply the coefficient of the first term by the constant <span> <span> 1</span> • -36 = -36</span> 

Step-2: Find two factors of  -36  whose sum equals the coefficient of the middle term, which is - 5.

<span><span>     -36   +   1   =   -35</span><span>     -18   +   2   =   -16</span><span>     -12   +   3   =   -9</span><span>     -9   +   4   =   -5   That's it</span></span>


Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -9  and  4 
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Step-4: Add up the first 2 terms, pulling out like factors :
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              Add up the last 2 terms, pulling out common factors :
                    4 • (x-9)
Step-5: Add up the four terms of step 4 :
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             Which is the desired factorization

<span>Equation at the end of step  1  :</span> (x + 4) • (x - 9) = 0 <span>Step  2  :</span>Theory - Roots of a product :

<span> 2.1 </span>   A product of several terms equals zero.<span> 

 </span>When a product of two or more terms equals zero, then at least one of the terms must be zero.<span> 

 </span>We shall now solve each term = 0 separately<span> 

 </span>In other words, we are going to solve as many equations as there are terms in the product<span> 

 </span>Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

<span> 2.2 </span>     Solve  :    x+4 = 0<span> 

 </span>Subtract  4  from both sides of the equation :<span> 
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Solving a Single Variable Equation :

<span> 2.3 </span>     Solve  :    x-9 = 0<span> 

 </span>Add  9  to both sides of the equation :<span> 
 </span>                     x = 9 

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