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Bess [88]
1 year ago
9

Which of the following is a result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units

Mathematics
2 answers:
Rufina [12.5K]1 year ago
7 0

Answer:

The general equation of the circle is given by:

(x-h)^2+(y-k)^2=r^2 where r is the radius of the circle and (h, k) is the center of the circle.

To shift any function upwards b units , then the center of the circle becomes;

(h, k+b)

As per the given statement:

equation of the circle is given by:

(x+3)^2+(y-2)^2=36

Center of this circle is: (-3, 2) and radius(r) = 6

to shift this equation of circle 3 units up then;

(h, k+3) = (-3, 2+3) = (-3, 5)

then;

the equation of circle 3 units upwards with radius = 6 units and center = (-3, 5) become:

(x+3)^2+(y-5)^2=36

Therefore, the result of shifting a circle with equation

(x+3)^2+(y-2)^2=36   up 3 units is:

 (x+3)^2+(y-5)^2=36

sdas [7]1 year ago
4 0
Answer: A result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units is: (x+3)^2+(y-5)^2=36

To shift a graph "a" units up, we must replace in the equation "y" by "y-a" when y is not isolated; or if y is isolated, you add "a" to the right side of the equation.
In this case we want to shift the graph of the circle 3 units up, then a=3, and we must replace in the equation of the circle "y" by "y-3":
(x+3)^2+[(y-3)-2]^2=36→
(x+3)^2+(y-3-2)^2=36→
(x+3)^2+(y-5)^2=36

Answer: A result of shifting a circle with equation (x+3)^2+(y-2)^2=36 up 3 units is: (x+3)^2+(y-5)^2=36
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Answer:

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2 years ago
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How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1
Zielflug [23.3K]

Answer:

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Step-by-step explanation:

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The expression can't be further simplified;

Hence, \frac{5}{-3} - \frac{4}{2} + \frac{1}{-3} = -\frac{8}{3}

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On a road map, the locations A, B and C are collinear. Location C divides the road from location A to B, such that AC:CB = 1:2.
koban [17]

Answer:

C. (-1,-2)

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So x = (mx₂ + nx₁)/(m + n)

y = (my₂ + ny₁)/(m + n)

Substituting the values of the coordinates, we have

x = (mx₂ + nx₁)/(m + n)

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multiplying through by 3, we have

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multiplying through by 3, we have

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1 year ago
Which function has the domain x>or= -11
iogann1982 [59]
I'm assuming this is multiple choice and you forgot to post the answers. I'll take a guess and say it probably looks something like this:
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Because you can't take the square root of a negative number without getting an imaginary result, resulting in the function having a closed domain limit.
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2 years ago
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