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taurus [48]
1 year ago
10

On a coordinate plane, a parabola opens up. It starts in quadrant 1, crosses the x axis where the vertex is in quadrant 4, and c

rosses the x-axis back into quadrant 1. Which function could be represented by the graph on the coordinate plane? f(x) = (x – 8)2 + 6 f(x) = (x + 8)2 + 6 f(x) = (x + 8)2 – 6 f(x) = (x – 8)2 – 6
Mathematics
2 answers:
sp2606 [1]1 year ago
8 0

Answer:

The answer for this question is <u>f(x) = (x - 8)2-6</u>.

andrew-mc [135]1 year ago
6 0
F(x) = (x - 8)2-6

if you simplify the equation you’re left with f(x) = (x - 8) - 4. there are two transformations that can be derived from this equation: translate horizontally right 8 and translate vertically down 4. because the parabola starts in quadrant 1, the parabola needs to be translated right opposed to left to match this. since the parabola’s vertex is in the negative quadrant 4, the function needs to be moved down which matches the second vertical translation the equation gives us.
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Xavier is working two summer jobs, making $14 per hour lifeguarding and $15 per hour tutoring. Xavier must earn at least $170 th
Julli [10]

Answer:

Step-by-step explanation:

8 0
1 year ago
Liam has a bag of b beads. He gives 20 beads to his sister. He then makes 4 necklaces with the same of beads on each necklace us
grin007 [14]

Given :

Liam has a bag of b beads.

He gives 20 beads to his sister.

He then makes 4 necklaces with the same of beads on each necklace using all of the remaining beads.

To Find :

Write an expression that represents the number of beads on each necklace.

Solution :

Number of necklace remains after giving 20 beads to his sister is ( b - 20 ).

Number of beads on each necklace using all of the remaining beads  is :

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6 0
1 year ago
The graph represents the feasible region for the system:
morpeh [17]

We have been given a system of inequalities and an objective function.

The inequalities are given as:

y\leq 2x\\&#10;x+y\leq 45\\&#10;x\leq 30\\

And the objective function is given as:

P=25x+20y

In order to find the minimum value of the objective function at the given feasible region, we need to first graph the region.

The graph of the region is shown below:

From the graph, we can see that corner points of the feasible region are:

(x,y) = (15,30),(30,15) and (30,60).

Now we will evaluate the value of the objective function at each of these corner points and then we will compare which of those values is minimum.

\text{At (15,30)}\Leftrightarrow P=25\cdot 15+20\cdot 30=975\\&#10;\text{At (30,15)}\Leftrightarrow P=25\cdot 30+20\cdot 15=1050\\&#10;\text{At (30,60)}\Leftrightarrow P=25\cdot 30+20\cdot 60=1950\\

Hence the minimum value of objective function is 975 and it occurs at x = 15 and y = 30

3 0
2 years ago
Read 2 more answers
Given: Two concentric circles with Center Point p. How many tangent lines can be drawn that both circles share?
levacccp [35]

Answer: I think that it's not One but It's <u><em>ZERO</em></u> because a tangent line can only touch the circle at one point and if it touches the small circle once it would have to go through the larger one twice.

Edit: I just checked and it's definitely<u><em> ZERO</em></u>

7 0
1 year ago
Decrease £16870 by 3% , give your answer rounded 2 decimal places
lidiya [134]
To decrease it by 3% we need to fine 97% of it and 97% is the same as 0.97

16870 times 0.97=16363.9

16870 decreased by 3% is 16363.9

I hope I've helped!
5 0
1 year ago
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