To solve the problem, get the
percentage of each test by multiplying the score and the percentage then add it all up:
82 * .25 (highest test grade) + 65* .15 (lowest test grade) +
71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework
grade)
= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number
The perimeter of the original rectangle is:
P = 2w + 2l = 70
The area of the original rectangle is:
A = w * l = 250
Then, by modifying the length of its sides we have:
Perimeter:
P '= 2 (2w) +2 (2l)
Rewriting:
P '= 2 (2w + 2l)
P '= 2P
P '= 2 (70)
P '= 140
Area:
A '= (2w) * (2l)
Rewriting:
A '= (2) * (2) (w) * (l)
A '= 4 * w * l
A '= 4 * A
A '= 4 * 250
A '= 1000
Answer:
the new area and the new perimeter are:
P '= 140
A '= 1000
Answer:
∠N and ∠Y
Step-by-step explanation:
When two triangles are congruent then there corresponding parts ( angle or sides ) are also congruent or equal, ( CPCTC )
In triangles MNO and XYZ,
Side MN, NO and OM are corresponding to XY, YZ and ZX respectively,
And, angles M, N and O are corresponding to angles X, Y and Z respectively,
Thus, if ΔMNO ≅ ΔXYZ
By CPCTC,
MN ≅ XY
NO ≅ YZ
OM ≅ ZX
Also, ∠M ≅ ∠X, ∠N ≅ ∠Y and ∠O ≅ ∠Z
Hence, THIRD OPTION is correct.
Answer:
Step-by-step explanation:
The best option is for the consultant to remove these data points because they are outliers. Unusual data points which are located far from rest of the data points are known as outliers.
