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2 years ago

7

At Central High School, there are 48 football players and 20 cheerleaders. What is the ratio of cheerleaders to football players

?

2 answers:

Ahat [919]2 years ago

6 0

Answer:

5 : 12

Step-by-step explanation:

Cheerleaders : football players

20 : 48

5 : 12

exis [7]2 years ago

6 0

Answer:

$5:12$

Step-by-step explanation:

Number of football players = 48

Number of cheerleaders= 20

The ration of cheerleaders to the football players is:

= $\frac{Cheerleaders}{Footbvallplayers} =\frac{20}{48} \\\\ \frac{10}{24}\\$

= $\frac{5}{12}$

So, the ratio of cheerleaders to football players is

$\frac{Cheerleaders}{Football players} =\frac{5}{12}$

or

$5:12$

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Answer:

Step-by-step explanation:

A car traveled at a constant speed as shown in the graph.

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Point A(3.5, 210) shows,

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Time to travel = 3.5 hours

So the point (3.5, 210) shows the distance traveled by the car in 3.5 hours is 210 miles.

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= $\frac{210}{3.5}$

= 60 mph

Now we will find the speed of the car at another point B(1, 60).

If the speed of car is same as the point B as of point A, point B will lie on the graph.

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= $\frac{60}{1}$

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1 year ago

The picture shows a person taking a pinhole photograph of himself. Light entering the opening reflects his image on the wall, fo

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2 years ago

Read 2 more answers

Christian is going to invest $310 and leave it in an account for 20 years. Assuming the interest is compounded daily, what inter

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Answer:

r=5.86%

Step-by-step explanation:

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1 year ago

goblinko [34]

Answer:

coordinate of point A is (a,b)

coordinate of point C is (2c,d)

slope of AD and BC = $\frac{b}{a-c}$

Step-by-step explanation:

According to midpoint formula

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the coordinate (x,y) of mid point of line PQ is given by

$x=\frac{x_{1} +x_{2} }{2}$ and $y=\frac{y_{1} +y_{2} }{2}$

now from the given diagram A is the mid point of line joining R(0,0) and S(2a,2b)

Using midpoint formula, coordinates of point A is given by

$x=\frac{0+2a}{2}= a$ and $y=\frac{0+2b}{2} =b$

so we have

coordinate of point A is (a,b)

Also C is the midpoint of line joining T (2c,2d) and V(2c,0)

coordinate of point C is given by

$x= \frac{2c+2c}{2} =2c$ and $y=\frac{2d+0}{2} =d$

so we have

coordinate of point C is (2c,d)

it is given that coordinate of point B is (a+c, b+d) and coordinate of D is (c,0)

If we have points P $(x_{1} ,y_{1} )$ and Q $(x_{2} ,y_{2} )$

then the slope of PQ = $\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

hence slope of AD= $\frac{0-b }{c-a}$

= $\frac{-b}{c-a}$

= $\frac{-b}{-(a-c)}$

= $\frac{b}{a-c}$

and slope of BC = $\frac{d-(b+d)}{2c-(a+c)}$

= $\frac{d-b-d}{2c-a-c}$

= $\frac{-b}{c-a}$

= $\frac{b}{a-c}$

so we have

slope of AD and BC = $\frac{b}{a-c}$

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1 year ago

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e-lub [12.9K]

Answer:

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Step-by-step explanation:

Given that, profit is quoted using the function :

R = 2pe ^ -0.1p

(a)

When price 'p' = $5

R = 2(5)e^(-0.1*5)

R = 10e^(-0.5)

R = 10 * 0.6065306

R = 6.065

B)

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R = 2(10)e^(-0.1*10)

R = 20e^(-1)

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R = 7.358

C.)

When price 'p' = $15

R = 2(15)e^(-0.1*15)

R = 30e^(-1.5)

R = 30 * 0.2231301

R = 6.694

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1 year ago