Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Answer:

Step-by-step explanation:
Line q will be graphed on the same grid. The only solution to the system of linear equations formed by lines n and q occurs when x =
and y = 0.
Now, as x =
is a solution of the equation, y = f(x) = 0, so,
will be a factor of the linear function y = f(x).
Therefore, we can write the possible equation for the line q will be
. (Where k is any constant} (Answer)