Answer:
The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B
Step-by-step explanation:
Given as :
The distance drove by Jack Duffy = d = 12,568 miles
The fixed costs totaled = $1,485.00
The variable cost totaled = $2,015.75
Let The cost per mile that Jack Duffy charge = $x cost per miles
Now, According to question
The totaled cost = The fixed costs + The variable cost
Or, The totaled cost = $1,485.00 + $2,015.75
I.e The totaled cost = $3500.75
Now,
The cost per mile that Jack Duffy charge = 
I.e x = 
∴ x = $0.278 per miles
So,The cost per mile that Jack Duffy charge = x = $0.278 per miles .
Hence,The cost per mile that Jack Duffy charge $0.278 per miles , i.e option B Answer
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:
So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{25}}=\frac{1}{5}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cfrac%7B1%7D%7B5%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
I'm assuming that this is the complete question.
If f(x) = 3 – 2x and g(x)=1/(x+5), what is the value of (f/g)(8)? a) –169 b) –1 c) 13 d) 104
x = 8
f(x) = 3 -2xf(8) = 3 - 2(8) = 3 - 16 = -13
g(x) = 1/(x+5)g(8) = 1/(8+5) = 1/13
(f/g)(8)f(8)/g(8) = -13/ (1/13) = -13 * 13 = -169 Choice A :)
Number of stocks held = 30
Price at which each shares of Lofty Cheese Company bought = 20 1/4
= (81/4) dollars
Price at which each shares of Lofty Cheese Company sold = 25 1/4
= (101/4) dollars
Amount of profit made per share of Lofty Cheese Company = [(101/4 - (81/4)] dollars
= (20/4) dollars
= 5 dollars
Amount of profit made for 30 shares of Lofty Cheese Company = (30 * 5) dollars
= 150 dollars.
So you will make a profit of $150.The correct option in regards to the question given is option "C".
Answer:
26.11% of women in the United States will wear a size 6 or smaller
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
In the United States, a woman's shoe size of 6 fits feet that are 22.4 centimeters long. What percentage of women in the United States will wear a size 6 or smaller?
This is the pvalue of Z when X = 22.4. So
has a pvalue of 0.2611
26.11% of women in the United States will wear a size 6 or smaller
