Answer:
The sample of sizes 2 and their mean are given below.
Step-by-step explanation:
The population consist of 5 values, S = {1, 3, 4, 4, 6}.
The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

Th formula to compute the mean is:

List the 10 samples and their mean as follows:
<u>Sample</u> <u>Mean</u>
(1, 3) ![\bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B3%5D%3D%5Cfrac%7B4%7D%7B2%7D%3D2.0)
(1, 4) ![\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B4%5D%3D%5Cfrac%7B5%7D%7B2%7D%3D2.5)
(1, 4) ![\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B4%5D%3D%5Cfrac%7B5%7D%7B2%7D%3D2.5)
(1, 6) ![\bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B6%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 4) ![\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B4%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 4) ![\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B4%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 6) ![\bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B6%5D%3D%5Cfrac%7B9%7D%7B2%7D%3D4.5)
(4, 4) ![\bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B4%5D%3D%5Cfrac%7B8%7D%7B2%7D%3D4.0)
(4, 6) ![\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B6%5D%3D%5Cfrac%7B10%7D%7B2%7D%3D5.0)
(4, 6) ![\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B6%5D%3D%5Cfrac%7B10%7D%7B2%7D%3D5.0)
Inequality:
5x - 3 ≤ 28
Answer:
5x - 3 <span>≤ 28
5x </span><span>≤ 31
x </span><span>≤ 31/5 or 6.2 ($6.20)</span>
If Ian uses 1/20 of the ketchup 4 times, this is equal to 4/20, or

.

can be simplified to

, which means we need to work out

of 12.2

is equivalent to 20%, which as a decimal is 0.2
0.2 x 12.2 = 2.44 - however, this is how much he has
used, and we need to figure out how much is left.
12.2 - 2.44 = 9.76
So, Ian has 9.76 oz remaining :)
A) He wanted to create zero pairs on the left side of the equation to get a positive coefficient of x on the right side