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suter [353]
1 year ago
7

The LaSalle High School senior class raised funds for an end of the year cruise getaway. The city gave them a special package fo

r the port fees and taxes - a flat fee of $1,500 for the entire class's port fees and taxes. It costs $367 per student to board the cruise. If your class raised $16,600, how many students can attend?
Mathematics
1 answer:
Brilliant_brown [7]1 year ago
3 0
Knowns:
C = mx + b
m = 367
b = 1500

C = 367x + 1500

Cost (c) = 16,600

16600 = 367x + 1500
subtract 1500 from both sides

15,100 = 367x
Divide both sides by 367

x = 41.14

41 Students can attend the trip!  Hope this helps



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360/6 = 60 degrees

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6 0
2 years ago
josh is 6 years older than 4 times Kim's age. The sum of their ages is less than 31. what is the oldest Kim could be? show all y
Mice21 [21]

Answer:

4 years old.

Step-by-step explanation:

Lets say that Josh's age is j and Kim's age is k. As Josh is 6 years older than 4 times Kim's age, we can write this as an equation:

j = 4k + 6

This is, John's age is equal to four times Kim's plus 6 years.

We then know that, when summed their ages is less than 31, so:

k + j < 31

Replace John's age by our first equation:

k + 4k + 6 < 31

5k + 6 < 31

Subtract 6 in both sides:

5k + 6 - 6 < 31 - 6

5k < 25

Dividing both sides by 5:

5k/5 < 25/5

k < 5

So, Kim's age MUST be less than 5.

If we talk about discrete values, this is 1, 2, 3, 4, 5, 6...., we will say than the oldest Kim could be is 4. If Kim is 5 years old, the sum of ages is 31 and we need it ti be LESS than 31. (we are not considering fractional numbers as 4.5 years old).

So, Kim can be, at maximum, 4 years old.

7 0
1 year ago
The following two sets of parametric functions both represent the same ellipse. Explain the difference between the graphs.
statuscvo [17]
The answer
ellipse main equatin is as follow:

X²/ a²   +  Y²/ b²  =1, where a≠0 and b≠0

for the first equation: <span>x = 3 cos t and y = 8 sin t
</span>we can write <span>x² = 3² cos² t and y² = 8² sin² t
and then  </span>x² /3²= cos² t and y²/8² =  sin² t
therefore,  x² /3²+ y²/8²  =  cos² t + sin² t = 1
equivalent to x² /3²+ y²/8²  = 1

for the second equation, <span>x = 3 cos 4t and y = 8 sin 4t we found
</span>x² /3²+ y²/8²  = cos² 4t + sin² 4t=1

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