Answer:
R(x) is your answer
Step-by-step explanation:
Answer:
we have to maximize the following equation:
45A + 50B + 55C
where:
A = number of model A bicycles produced
B = number of model B bicycles produced
C = number of model C bicycles produced
the constraints are:
2A + 2.5B + 3C ≤ 4006 (assembly constraint)
A + 0.5B + 2C ≤ 2495 (painting constraint)
A + 0.75B + 1.25C ≤ 1500 (packaging constraint)
A,B,C ≥ 0
using solver, the optimal solution is: 745A + 1006B = $83,825
using slack variables:
2A + 2.5B + 3C + S1 = 4006 (assembly constraint)
A + 0.5B + 2C + S2 = 2495 (painting constraint)
A + 0.75B + 1.25C + S3 = 1500 (packaging constraint)
A,B,C,S ≥ 0
slack variable tableau:
A B C S1 S2 S3 Z B
2 2.5 3 1 0 0 0 4006
1 0.5 2 0 1 0 0 2495
<u>1 0.75 1.25 0 0 1 0 1500</u>
-45 -50 -55 0 0 0 1 0
You substract 64 from 48 and then that would lead you to 16y=16. Divide 16 by 16 to get y=1
All of these numbers are making me crazy
Since the range of the scores given was between 300 and 700 (which is 2 standard deviations below and above the mean), the probability that a randomly selected student's math score - as based on the empirical rule of statistics - is 95%. In decimal form, it is .95.
