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Alja [10]
1 year ago
11

Find the 11th term of the following geometric sequence. 10, 50, 250, 1250

Mathematics
2 answers:
Natasha2012 [34]1 year ago
8 0

Answer:

97656250

Step-by-step explanation:

keep multiplying each term by 5 until you get to the 11th one. the 11th term is 97656250

Kazeer [188]1 year ago
3 0
To find the nth term do you know the equation
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Find the value of cosAcos2Acos3A...........cos998Acos999A where A=2π/1999
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Hello,

Here is the demonstration in the book Person Guide to Mathematic by Khattar Dinesh.

Let's assume
P=cos(a)*cos(2a)*cos(3a)*....*cos(998a)*cos(999a)
Q=sin(a)*sin(2a)*sin(3a)*....*sin(998a)*sin(999a)

As sin x *cos x=sin (2x) /2

P*Q=1/2*sin(2a)*1/2sin(4a)*1/2*sin(6a)*....
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= 1/(2^999) * sin(2a)*sin(4a)*...
     *sin(998a)*sin(1000a)*sin(1002a)*....*sin(1996a)*sin(1998a)
 as sin(x)=-sin(2pi-x) and 2pi=1999a

sin(1000a)=-sin(2pi-1000a)=-sin(1999a-1000a)=-sin(999a)
sin(1002a)=-sin(2pi-1002a)=-sin(1999a-1002a)=-sin(997a)
...
sin(1996a)=-sin(2pi-1996a)=-sin(1999a-1996a)=-sin(3a)
sin(1998a)=-sin(2pi-1998a)=-sin(1999a-1998a)=-sin(a)

So  sin(2a)*sin(4a)*...
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= sin(a)*sin(2a)*sin(3a)*....*sin(998)*sin(999) since there are 500 sign "-".

Thus
P*Q=1/2^999*Q or Q!=0 then
P=1/(2^999)

       








7 0
1 year ago
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Harry put blue and green marbles in a bag. Exactly 3/4 of the marbles in the bag are blue. Which of the following could be the t
pantera1 [17]

Answer:

D

Step-by-step explanation:

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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
tia_tia [17]
<h3>Answer:  6.93</h3>

Work Shown:

Use the pythagorean theorem to find x

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