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2 years ago

Find the 11th term of the following geometric sequence. 10, 50, 250, 1250

Mathematics

2 answers:

Natasha2012 [34]2 years ago

8 0

Answer:

97656250

Step-by-step explanation:

keep multiplying each term by 5 until you get to the 11th one. the 11th term is 97656250

Kazeer [188]2 years ago

3 0

To find the nth term do you know the equation

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A process engineer is implementing a quality assurance system on a breakfast cereal production line. A new sensor is installed o

nataly862011 [7]

Answer:

0.2%

Step-by-step explanation:

The given parameters are;

The percentage of product within the correct range = 95%

The percentage of the times the sensor reject boxes of incorrect weight = 98%

The percentage of the times the company reject boxes with correct weight = 1%

$\begin{array}{cccc}&P&N&T\\P&TP&0.9&90\\N&FP&9.8&10\end{array}$

We have, FN = 0.9, TN = 9.8, TP = 90 - 0.9 = 89.1, FP = 10 - 9.8 = 0.2

FNR = FN/(FN + TP) = 0.9/(0.9 + 89.1) = 0.01

FPR = 0.2/(0.2 + 9.8) = 0.02

TPR = 89.1/(89.1 + 0.9) = 0.99

TNR = 9.8/(9.8 + 0.2) = 0.98

P(C/A) = TPR × P(C)/((TPR × P(C) + FPR×(1 - P(C)))

Where;

P(C/A) = The probability that a correct weight package is accepted

∴ P(C/A) = 0.99*0.9/(0.99*0.9 + 0.02*0.1) ≈ 0.99776

The probability that a correctly weighed package is rejected, P(C/R), is given as follows;

P(C/R) = 1 - P(C/A)

∴ P(C/R) ≈ 1 - 0.99776 = 0.00224 ≈ 0.2%

The probability that a correctly weighed package is rejected, P(C/R) ≈ 0.2%

5 0

2 years ago

A trapezoid has a base of 4.5 inches, a height of 6 inches, and an area of 21 square inches. The equation below can be used to d

Troyanec [42]

Answer:

$b_2 = -2.5$

Step-by-step explanation:

Given

$\frac{1}{2}(4.5 + b_2) * 6 = 21$

Required

Determine the value of T

$\frac{1}{2}(4.5 + b_2) * 6 = 21$

Multiply both sides by 2

$2 * \frac{1}{2}(4.5 + b_2) * 6 = 21 * 2$

$(4.5 + b_2) * 6 = 42$

Divide through by 6

$4.5 + b_2 = 42/6``$

$4.5 + b_2 = 7$

$b_2 = 7 - 4.5$

$b_2 = -2.5$

6 0

2 years ago

In 2012, on average, about $9.46\times10^{-1}$ pound of potatoes was produced for every $2.3\times10^{-5}$ acre harvested. How m

muminat

Answer:

4.113 × 10⁴ pounds per acre = 41,130 pounds per acre to the nearest pounds per acre

Step-by-step explanation:

9.46 × 10⁻¹ pounds of potatoes were produced for every 2.3 × 10⁻⁵ acre harvested. The average pounds of potatoes harvested per acre would be pounds of potatoes/acres harvested = 9.46 × 10⁻¹ pounds/2.3 × 10⁻⁵ acre = 4.113 × 10 ⁻¹⁻⁻⁵ = 4.113 × 10⁵⁻¹ = 4.113 × 10⁴ pounds per acre = 41,130 pounds per acre to the nearest pounds per acre.

6 0

2 years ago

Find the area under the standard normal curve to the right of z=1.9

tresset_1 [31]

To find the area to the right of a positive z-score, begin by reading off the area in the standard normal distribution table. Since the total area under the bell curve is 1, we subtract the area from the table from 1. For example, the area to the left of z = 1.02 is given in the table as .846.

6 0

2 years ago

A researcher is testing how bacterial cells react to different environments. She placed a petri dish that initially had 32,000 b

Nataly [62]

<u>Solution- </u>

A researcher placed a petri dish with 32,000 bacterial cells. One hour after being placed in the vacuum chamber, the number of cells in the petri dish had halved. Another hour later, the number of cells had again halved.

This can be represented as exponential decreasing function,

$y=a(1 - r)^x$