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Alja [10]
1 year ago
11

Find the 11th term of the following geometric sequence. 10, 50, 250, 1250

Mathematics
2 answers:
Natasha2012 [34]1 year ago
8 0

Answer:

97656250

Step-by-step explanation:

keep multiplying each term by 5 until you get to the 11th one. the 11th term is 97656250

Kazeer [188]1 year ago
3 0
To find the nth term do you know the equation
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A length is measured as 21cm correct to 2 significant figures. what is the upper bound for the length?​
Leno4ka [110]

the upper bound for the length is  21.5  cm .

<u>Step-by-step explanation:</u>

Lower and Upper Bounds

  • The lower bound is the smallest value that will round up to the approximate value.
  • The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒ 21.5  cm

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is  21.5  cm .

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Triangle N T M is shown. Angle N T M is a right angle. An altitude is drawn from point T to point U on side N M to form a right
stich3 [128]

Answer:

The value of y is 6\sqrt{3} units ⇒ 2nd answer

Step-by-step explanation:

In the attached figure

∵ ∠MTN is a right angle

∵ TU is the altitude of the triangle

- There are some rules in this triangle let us revise them

  • (NT)² = NU . NM
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- Simplify the root

∴ NT = 6\sqrt{3} units

∵ NT is y

∴ y = 6\sqrt{3} units

The value of y is 6\sqrt{3} units

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Answer: -5.5

Step-by-step explanation:

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