The owner is most likely cheating because it is usually a 50|50 chance of winning. But, you usually only get 50, and win a bit less and loose more. So, he is most likely cheating. (Hope this helped :D)
Hence the circumference of the circle is: 6π or 18.84 units
(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.
Answer: D. 41 cm
There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,
a^2+b^2 = (b+1)^2
a^2 + b^2 = b^2 + 2b +1
a^2=2b+1
So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.
b = (a^2 - 1)/2
a=3, b=(3^2-1)/2=4, c=b+1=5
a=5, b=(5^2-1)/2 =12, c = 13
a=7, b=24, c=25
a=9, b=40, c=41
a=11, b=60, c=61
a=13, b=84, c=85
It's good to be able to recognize Pythagorean Triples when we see them.
Otherwise we'd have to work the calculator:
√(9² + 40²) = √1681 = 41
Answer:
The area of the shaded region is 
Step-by-step explanation:
<u><em>The correct question is</em></u>
A circle with radius of 4cm sits inside a circle with a radius of 11cm. What is the area of the shaded region?
The shaded region is the area outside the smaller circle and inside the larger circle
we know that
To find out the shaded region subtract the area of the smaller circle from the area of the larger circle
so
simplify
where
r_a is the radius of the larger circle
r_b is the radius of the smaller circle
we have
substitute
assume
substitute
I believe the correct answer from the choices listed above is the first option. If the sides of a square are five to the power of two fifths inches long, then the are of the square would be <span>five to the power of four fifths square inches. Hope this answers the question.</span>
