Ask question

Ask question

All categories

2 years ago

6

On the way to her babysitting job, Mary rode her bike for the first mile. She stopped at a traffic light and waited a few minute

s for the traffic light to turn green. She then walked her bike across the street and up a short steep hill. Finally, she rode the bike at a constant speed for one more mile. If Mary created a graph of her time and distance, which statement describes the part of her graph that would show no change in distance? Mary used her bike to ride the first mile. Mary stopped and waited for the traffic light to turn green. Mary walked her bike across the avenue and up a short hill. Mary rode her bike at a constant speed for one mile.

2 answers:

Aloiza [94]2 years ago

7 0

The answer is b, hope this helps

tensa zangetsu [6.8K]2 years ago

3 0

Step-by-step explanation: Answer is B

You might be interested in

"a man drove 10 mi directly east from his home, made a left turn at an intersection, and then traveled 2 mi north to his place o

jasenka [17]

When you think of the situation as a whole, you may notice that the lines in the problem actually form a triangle. First, the man driving 10 miles east forms a bottom leg of the triangle 10 units long. When he drives the 2 miles north, he adds another leg of 2 units length. When the place of work is connected to the starting position through a line, a third and final line is drawn which creates the triangle.

So, how can we find the direct distance from his place of work to his home? We can use the Pythagorean Theorem ( $a^2 + b^2 = c^2$ , where $a$ and $b$ are the lengths of the legs of the triangle and $c$ is the length of the hypotenuse). We know that the lengths of the legs are 10 and 2, which we can use in the formula, as shown below:

$(10)^2 + (2)^2 = c^2$

Now, we can solve this equation for $c$ :

$\sqrt{(10)^2 + (2)^2} = c$

$\sqrt{104} = c \approx 10.2$

The distance would be √104 miles, or approximately 10.2 miles.

4 0

2 years ago

Rob borrows $15.00 from his father, and then he borrows $3.00 more. Drag numbers to write an equation using negative integers to

Paul [167]

Answer:

Rob owes his father=-$15-$3= -$18

Step-by-step explanation:

Rob borrows $15 first and then $3.

Since we have to use negative integers, so

-$15-$3= -$18

4 0

1 year ago

Read 2 more answers

in the diagram below, <AFB = <EFD. if m<EFD = (5x+6)°, m<DFC = (19x-15)°, and m<EFC = (17x+19)°, find m<AFE

NeX [460]

Answer:

m<AFE = 128°.

Step-by-step explanation:

<u>Step 1: Find the value of x</u>

<em>Angle EFD + Angle DFC = Angle EFC</em>

5x + 6 + 19x - 15 = 17x + 19

24x - 9 = 17x + 19

7x = 28

x = 4

<u>Step 2: Find all angles</u>

<em>Angle AFB=Angle EFD= 5x + 6</em>

5(4) + 6 = 26°

Angle DFC = 19x - 15

19(4) - 15 = 61°

<u>Step 3: Find angle AFE</u>

<em>Line BD is a straight line and all angles on a straight line are equal to 180°.</em>

<em>Angle AFB + Angle AFE + Angle EFD = 180°</em>

26 + BFC + 26 = 180°

BFC = 180 - 52

BFC = 128°

<em>Therefore, m<AFE is equal to 128°.</em>

!!

3 0

1 year ago

Rachel has completed 2/3 of her shift; Jose has completed 1/6 of his shift; Damon has finished 4/5 of his shift; and Stacy has 6

Alisiya [41]

Answer:

C. Stacy

Step-by-step explanation:

One way to compare is to convert all the fractions into decimals

Rachel works 2/3 of her shift: Approximately= 0.667

Jose works 1/6: approx. = 0.1667

Damon works 4/5= 0.80

Stacy works 6/7: approx. = 0.8571

Now this makes it much easier to compare

And since 0.85714 (Stacy's shift) is the largest number, Stacy has completed the largest portion of her shift

4 0

1 year ago

Your utility company charges 13 cents per kilowatt-hour of electricity. What is the daily cost of keeping lit a 75 watt light bu

Tresset [83]

we know that

$1 Kw=1000 w$

The company charges $13$ cents per kilowatt-hour of electricity

$13 cents=0.13 dollars\\\\ 75w=\frac{75}{1000} kw\\\\ 15w=\frac{15}{1000} kw$

Step $1$

Find the cost for the light bulb

a) in one day

$\frac{75}{1000} *12=0.9\ kw\ hour$

$Cost=0.13*0.9$

Cost=$ $0.117$

b) In a year

$\frac{75}{1000} *12=0.9\ kw\ hour$

$0.9*365=328.5\ kw\ hour$

$Cost=0.13*328.5$

Cost=$ $42.71$

Step $2$

Find the cost for the led bulb

a) in one day

$\frac{15}{1000} *12=0.18\ kw\ hour$

$Cost=0.13*0.18$

Cost=$ $0.0234$

b) In a year

$\frac{15}{1000} *12=0.18\ kw\ hour$

$0.18*365=65.7\ kw\ hour$

$Cost=0.13*65.7$

Cost=$ $8.54$

Step $3$

Find the difference in cost

$Save=42.71-8.54\\ Save=34.17 dollars$

therefore

the answer is

$34.17 dollars$

3 0

2 years ago

Read 2 more answers