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LekaFEV [45]
2 years ago
13

The population of a city is 1,503,049. The land area of the city is 181.5 km².

Mathematics
2 answers:
Ksenya-84 [330]2 years ago
7 0
Population density is population divided by area. So 

City: 1,503,049 people / 181.5 km^2 = <span> <span>8281.262 = 8281 people/km^2

Watering hole. Same thing, population divide by area. Only gotcha is the area needs to be calculated. Using A = pi r^2, you get
3.14 * (34 km)^2 = </span></span><span> <span>3629.84 km^2

32/3629.84 = </span></span><span> 0.008816 = 0 </span><span>antelopes/km

Chunk of </span><span>mahogany wood.
</span>Take the volume and multiply by the density. So
1728 cm^3 * 0.71 g/cm^3 = <span> <span>1226.88 g

Gold bar.
Same thing. Volume multiplied by density. So
51.8 cm^3 * 19.3 g/cm^3 = </span></span><span> <span>999.74 g
</span></span>
And finally, the sugar maple. This one is slightly trickier. You first need to calculate the volume of the block of wood. So divide the mass by the density.

82.8 g / 0.69 g/cm^3 = <span> <span>120 cm^3

Now you know the length and width are 5x4 = 20 cm^2. So calculate the height by dividing the volume by 20 cm^2. So
120 cm^3 / 20 cm^2 = 6 cm.

</span></span>
Tresset [83]2 years ago
5 0
1.) 8,281 people/km²
2.)
3.) 1226.88 grams
4.) 999.74 grams
5.) 6

I am not sure about number 2. 
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Round 3,872.3155 to the nearest hundred
zlopas [31]

Answer:

3,872.32

Step-by-step explanation:

the nearest hundredth is 2 numbers on the right of the decimal sign. So you round up from 5 to get answer above.

6 0
2 years ago
Find a26 in the arithmetic sequence: -15, -35, -55, -75
MrRissso [65]

Answer: x=−5

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−4−7x=31

−4+−7x=31

−7x−4=31

Step 2: Add 4 to both sides.

−7x−4+4=31+4

−7x=35

Step 3: Divide both sides by -7.

−7x

−7

=

35

−7

x=−5

4 0
2 years ago
Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)
tigry1 [53]

Answer:

M(x,y) = (1,3) belongs to the line y = 2\cdot x +1. Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

y=k\cdot x + b

Where:

x - Independent variable, dimensionless.

y - Dependent variable, dimensionless.

k - Slope, dimensionless.

b - y-Intercept, dimensionless.

If we know that b = 1, x = 1 and y = 3, then we clear slope and solve the resulting expression:

k = \frac{y-b}{x}

k = \frac{3-1}{1}

k = 2

Then, we conclude that point M(x,y) = (1,3) belongs to the line y = 2\cdot x +1, whose graph is presented below.

3 0
2 years ago
A control chart is developed to monitor the analysis of iron levels in human blood. The lines on the control chart were obtained
sergejj [24]

Answer:

Step-by-step explanation:

Hello!

The variable is X: iron level on human blood.

It has a mean of μ= 51.50 mg/dl and a standard deviation of σ= 3.50 mg/dl.

According to the control chart, the process should be shut down for troubleshooting when the analysis shows values X[bar]≥ 53.42 mg/dl and X[bar]≤ 49.58 mg/dl

Warnings are received at levels X[bar]≥52.78 mg/dl and X[bar]≤ 50.22 mg/dl

The system works between levels 49.58<X[bar]<53.42 and works without warnings between 50.22<X[bar]<52.78.

Using these parameters you have to analyze if the lists of sample means to see which ones are within the working values are wich ones are outside this interval.

<u>Sample 1</u>

Min= 50.15

Max= 51.99

Mean= 51.61

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>This sample's min value is below the lower limit of the warning interval but not low enough to reach action levels, the max value is within the working range.</em>

<em><u /></em>

<u>Sample 2 </u>

Min= 50.32

Max= 52.56

Mean= 51.16

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both the max and min values of the sample are within the working range without warning.</em>

<em />

<u>Sample 3</u>

Min= 50.25

Max= 53.12

Mean= 51.83

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>The max value of this sample is above the upper limit of the warning interval but does not surpass the upper bond of the troubleshoot interval. Min value is within working values.</em>

<em />

<u>Sample 4</u>

Min= 50.05

Max= 53.01

Mean= 51.70

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values surpass the warning interval but do not reach action levels</em>.

<u>Sample 5</u>

Min= 50.35

Max= 52.71

Mean= 51.37

Without warning 50.22<X[bar]<52.78

Without Action interval 49.58<X[bar]<53.42

<em>Both min and max values are within working levels without warnings.</em>

<em />

Considering that samples reaching warning levels should be shut down as a precaution, they are classified as:

Shutdown: Sample 1, 3 and 4

Do not shutdown: Sample 2 and 5.

I hope it helps!

8 0
2 years ago
Vanna is saving for a trip. The hotel room will be $298.17 for 3 nights, and there will be additional fees. What is her daily co
docker41 [41]

Answer:

Step-by-step explanation:

Total cost for the three nights

Total_3 = $298.17 + 3*u

Where <em>u </em>represents the unknown fees for a single day

To find the daily cost, we divide the previous equation by three

Daily cost = ($298.17 + 3*u)/3

Daily cost = ($99.39 + u)

So, if we create an inequality for the daily cost

Let x = Daily cost

x > $99.39

She will pay more than $99.39 per night

7 0
2 years ago
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