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Marina CMI [18]
1 year ago
9

What is 2+2+6+7+7+9+6+7+5​

Mathematics
1 answer:
pentagon [3]1 year ago
4 0

Answer:

The answer would be 51

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In two or more complete sentences describe how to determine the appropriate model for the set of data, (0,2), (2,3), (5,4), (10,
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The very first thing to do in every correlation activity is to plot the gathered data points in a scatter plot. It is better to use software tools like MS Excel because they have a feature there that uses linear regression like that one shown in the picture.

Once you plot the data points, make a trendline. You are given with options. If you want a linear function, then you will have a linear model with a function equation of y = 0.2907x + 2.2643. It has a correlation coefficient of 0.9595. That's a strong correlation already. The R² value tells how good your model fits the data points. If you want to increase the R², a better model would be a quadratic function with the equation, y = -0.0209x²+0.506x+2.0232. As you can see the R² increase even more to 0.9992.

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The table shows y as a function of x. Suppose a point is added to this table. Which choice gives a point that preserves the func
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Answer:

<em>A) (-5,7)</em>

Step-by-step explanation:

<u>Functions and Relations</u>

A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).

By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

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2 years ago
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v(x) = 32,500(.92)^{x}

Plug two and three in for x

v(2) = 32,500(.92)^{2}

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v(2) = 27,500

v(3) = 32,500(.92)^{3}

v(3) = 32,500(.778688)

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Subtract v(3) from v(2)

27,500 - 25,307.36 = 2192.64

Round to the nearest dollar to get $2193

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