Answer:
Given Equation : x² = 8y
Given Equation matches with standard equation of parabola on positive y-axis
x² = 4ay
By comparing both equation we get,
4a = 8 ⇒ a = 2
Focus of parabola = ( 0 , 2 )
Vertex of parabola = ( 0 , 0 )
Axis of Symmetry = y-axis
To draw its, we find some points
when x = 4 or -4 we get
4² = 8y ⇒ 16 = 8y ⇒ y = 2
So, points are ( 4 , 2 ) and ( -4 , 2 )
when x = 8 or -8 we get
(-8)² = 8y ⇒ 64 = 8y ⇒ y = 8
So, points are ( 8 , 8 ) and ( -8 , 8 )
Graph from above points is attached.
Options
Answer:
(B) -2
Step-by-step explanation:
Given the list
This list has been arranged in order from the least to the greatest.
We are required to find an Integer that can be inserted on the blank line (I have used x) in the list.
An integer is defined as a positive or negative whole number.
Out of the given options, only -1 and -2 are integers. However:
Therefore, it cannot be our result.
The correct answer is -2.