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lapo4ka [179]
2 years ago
14

Which graph represents the equation x2 = 8y?

Mathematics
2 answers:
jarptica [38.1K]2 years ago
6 0

Answer:

Given Equation : x² = 8y

Given Equation matches with standard equation of parabola on positive y-axis

x² = 4ay

By comparing both equation we get,

4a = 8 ⇒ a = 2

Focus of parabola = ( 0 , 2 )

Vertex of parabola = ( 0 , 0 )

Axis of Symmetry = y-axis

To draw its, we find some points

when x = 4 or -4 we get

4² = 8y ⇒ 16 = 8y ⇒ y = 2

So, points are ( 4 , 2 ) and  ( -4 , 2 )

when x = 8 or -8 we get

(-8)² = 8y ⇒ 64 = 8y ⇒ y = 8

So, points are ( 8 , 8 ) and ( -8 , 8 )

Graph from above points is attached.

UNO [17]2 years ago
4 0
Direction: Opens up
Vertex: (0,0)
Focus: (0,2)
Axis of Symmetry: x=0
Directrix: y=-2
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Bryan has to take 8 classes for both Pro's to be the same price.

Step-by-step explanation:

Given,

Monthly charges of Pro at Windy = $20.00

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Let,

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Dividing both sides by 10

\frac{10x}{10}=\frac{80}{10}\\x=8

Bryan has to take 8 classes for both Pro's to be the same price.

Keywords: function, division

Learn more about division at:

  • brainly.com/question/12012120
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#LearnwithBrainly

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2 years ago
Tony addison obtained a 20-year, $45,000 mortgage loan from united savings with an interest rate of 8.5%. his monthly payment is
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As given,  

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In △XYZ, m∠Z = 34, x = 61 cm, and z = 42 cm. Find m∠X. Round your answer to the nearest tenth of a degree.
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\frac{\sin{Z}}{z}=\frac{\sin{X}}{x}
\\
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Cross multiplying gives us
61(sin 34) = 42(sin X)

Divide both sides by 42:
(61(sin 34))/42 = (42(sin X))/42
(61(sin 34))/42 = sin X

Take the inverse sine of both sides:
sin⁻¹((61(sin 34))/42) = sin⁻¹(sin X)
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1 year ago
7.8c + 6p - 3.4c - 10
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1 year ago
Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFraction right-parenthes
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Answer:

y-\frac{1}{3}=\frac{3}{4}(x-4)              

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we know that            

The equation of the line into point slope form is equal to                        

y-y1=m(x-x1)              

In this problem we have          

(x_1,y_1)=(4,\frac{1}{3})                            

m=\frac{3}{4}            

substitute the given values                

y-\frac{1}{3}=\frac{3}{4}(x-4)

therefore

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