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Nina [5.8K]
2 years ago
7

A spinner has four equally sized sectors that are numbered 2, 4, 4, and 5. The spinner is spun twice and the product of the outc

omes is found.
A fair decision is to be made about which one of four bushes will be planted.


The bush options are forsythia, lilac, hydrangea or dogwood.


Which description accurately explains how a fair decision can be made in this situation?

If the product of the spins is 8, a forsythia bush will be planted. If the product is 10, a lilac bush will be planted. If the product is 20, a hydrangea bush will be planted. If the product is 4, 16 or 25, a dogwood bush will be planted.

If the product of the spins is 8, a forsythia bush will be planted. If the product is 16, a lilac bush will be planted. If the product is 20, a hydrangea bush will be planted. If the product is 4, 10 or 25, a dogwood bush will be planted.

If the product of the spins is 8, a forsythia bush will be planted. If the product is 16, a lilac bush will be planted. If the product is 25, a hydrangea bush will be planted. If the product is 4, 10 or 20, a dogwood bush will be planted.

If the product of the spins is 8, a forsythia bush will be planted. If the product is 16, a lilac bush will be planted. If the product is 4 or 20, a hydrangea bush will be planted. If the product is 10 or 25, a dogwood bush will be planted.
Mathematics
1 answer:
JulsSmile [24]2 years ago
8 0

Answer:

Umm whats the question

Step-by-step explanation:

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PLEASE HELP A pizza parlor sells 320 pizzas per night when they charge $9.00 per pizza. The owner believes increasing the price
Sonja [21]
1. $9.00+$0.15=$9.15
2. 320-4=316
6 0
2 years ago
Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
2 years ago
Read 2 more answers
g In a survey of 500 residents, 300 were opposed to the use of the photo-cop for issuing traffic tickets.The standard error of t
Evgesh-ka [11]

Answer:

Z-score 1.96

Margin of error d= 0.04323

Step-by-step explanation:

Hello!

The study variable in this case is

X: Number of people that oppose the use of photo-cop for issuing traffic tickets in a sample of 500.

n= 500

The parameter of interest is the proportion of people that opposes it.

The estimated proportion is p'= 300/500= 0.6

To estimate the population proportion per Confidence interval you have to approximate the distribution of the sample proportion p' to normal:

p'≈N(p;p(1-p)1/n)

The mean of this distribution is p and the variance is p*(1-p)*1/n

To construct the Confidence interval, since the value of the population proportion is unknown, an estimated variance is used:

p'(1-p')*1/n ⇒ then the estimated standard error is √(p'(1-p')*1/n)

The formula for the confidence interval is:

p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

Where "Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }" represents the margin of error of the interval.

Now for a confidence level of 0.95 the value of Z is Z_{0.975}= 1.965

The estimated standard error is already calculated: \sqrt{\frac{p'(1-p')}{n} } = 0.022

The margin of error (d) is then:

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }= 1.965 * 0.022

d= 0.04323

I hope it helps!

7 0
2 years ago
A baseball is thrown up in the air. The table shows the heights y (in feet) of the baseball after x seconds.
kogti [31]

Answer:

Ok, we know that the baseball will have an equation like:

h(x) = a*x^2 + b*x + c

Where x represents time, and h(x) represents height.

Let's construct it:

The acceleration is:

a(t) = a

For the velocity, we can integrate over time and get:

v(x) = a*x + v0

where v0 is the initial vertical velocity.

and for the position (or the height) we can integrate again:

h(x) = a*x^2 + v0*x + h0

Where h0 is the initial position.

Then our equation is:

h(x) = a*x^2 + v0*x + h0.

Now let's look at the table:

when x = 0s, h(0s) = 6ft

Then:

h(0s) = a*0s^2 + v0*0s + h0 = 6ft

            h0 = 6ft.

We also can see that:

h(2s) = h(4s)

Knowing that the quadratic function has symmetry around a point, we can conclude that the point of symmetry is right in between of 2s and 4s, which is at x = 3s.

Now, for a standard quadratic equation:

a*x^2 + b*x + c

The symmetry line is at:

x = -b/2a

In this case:

b = v0

a = a

then we have:

3s  = -v0/(2*a)

v0 = -3s*(2a)

Now we have all the data that we need for our equation, we can write it as:

h(x) = a*x^2 - 6s*a*x + 6ft

Now we have only one variable left, we know that at x = 2s, h(2s) = 22ft

then:

h(2s) = 22ft = a*(2s)^2 - 6s*a*2s + 6ft

           22ft - 6ft = 16ft = a*(4s^2 - 12s^2) = a*(-8s^2)

                             16ft/(-8s^2) = a = -2ft/s^2

Then our equation is:

h(x) = (-2ft/s^2)*x^2 + (12ft/s)*x + 6ft

b) The height after 5 seconds is given by:

h(5s) =  (-2ft/s^2)*(5s)^2 + (12ft/s)*5s + 6ft = 16ft

7 0
2 years ago
There are 64 singers in the choir.The tenors and sopranos are in separate rows.There are 8 singers in each row.There are 4 rows
stealth61 [152]
4 rows because 4 times 8 equals 32, so then there are only 32 singers left. 64-32=32, and once again 4 times 8 equals 32.
7 0
1 year ago
Read 2 more answers
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