Answer:
4 sets
Step-by-step explanation:
The greatest common factor (GCF) of 16 and 12 is 4. This is the largest number that evenly divides 12 and 16. It can be found by looking at the factors of those numbers:
12 = 4·3
16 = 4·4
Or it can be found by seeing if the difference of the numbers (4) evenly divides them both. It does, so that is the GCF.
The greatest number of sets Mandy can make is 4.
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Each of Mandy's 4 sets will have 4 sheets of paper and 3 envelopes.
Answer:
The heights are the same after 4 hours.
Step-by-step explanation:
The red candle burns at a rate of 7/10 inches per hour. In t hours, (7/10)t inches have burned. The height of the candle after t hours is 8 - (7/10)t.
The blue candle burns at a rate of 1/5 inch per hour. In t hours, (1/5)t inches have burned. The height of the candle after t hours is 6 - (1/5)t.
You need to find the time, t, when their heights are equal.
8 - (7/10)t = 6 - (1/5)t
Multiply both sides by 10 (the LCD).
80 - 7t = 60 - 2t
-5t = -20
t = 4
The heights are the same after 4 hours.
<span>This question is a simple one. To answer this question, you need to understand the description in the question and determine to multiply or divide the number.
The first problem would be:
50.75 x 0.18= 9.135
</span>If you need to estimate, 50.75 is near 50; 0.18 is near 0.2 or 1/5 so it would be: 50/0.2= 10<span>
The second problem would be:
196 / 0.499: 392.785
If you need to estimate, 0.499 is near 0.5 then 196/0.5 would be 392</span>
Answer:Graph the image of the given triangle under a dilation with a scale factor of 12 and center of dilation (0, 0)
Answer:
24 terms
Step-by-step explanation:
The sum of an arithmetic sequence is the average of the first and last terms, multiplied by the number of terms. The last term is given by ...
an = a1 + (n-1)d
We have a sequence with first term a1 = 2 and common difference d = 2. So the last term is ...
an = 2+ 2(n -1) = 2n
Then the average of first and last terms times the number of terms is ...
Sn = 600 = n(2 + 2n)/2 = n(n+1) . . . . . . close to n²
We can solve the quadratic in n, or we can estimate the value of n as the integer just below the square root of 600.
√600 ≈ 24.5
so we believe n = 24.
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<em>Check</em>
S24 = 24·25 = 600 . . . . . . as required.
