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k0ka [10]
2 years ago
12

Prepare a prototype residual plot for each of the following cases: (1) error variance decreases with X; (2) true regression func

tion is U shaped, but a linear regression function is fitted.

Mathematics
1 answer:
Nadya [2.5K]2 years ago
3 0

Answer:

Please see attachment

Step-by-step explanation:

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Hint # 2 - Multiply the length, width, and height. The CORRECT answer will get Brainliest. If you can’t see zoom in. If you don’
Dvinal [7]
So you have to do 7x7x7 which your answer is 28cm^3
6 0
2 years ago
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Anna is at the movie theater and has $35 to spend. She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $
EastWind [94]

Answer with explanation:

Amount of money Possessed by Anna = $ 35

Money spent on ticket = $9.50

Money spent on Snacks = $ 3.50

Let x number of snacks, which will be least number of snacks that Anna can buy.

transforming the situation in terms of inequality

→9.50 +3.50 x≤ 35

→9.50 -9.50+3.50 x≤35-9.50

→3.50 x≤25.50

Dividing both sides by 3.50, we get

→x≤7.3(approx)

which can't be number of Snacks, as it will be an integral value.

So, minimum number of snacks with given amount of money = 7

So, Anna can buy snacks(x)={x:x≤7,x=1,2,3,4,5,6,7}=At most 7.

3 0
2 years ago
Read 2 more answers
The owner of a fish market determined that the mean weight for a catfish is 3.2 pounds with a standard deviation of 0.8 pound. A
madam [21]

Answer: The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is 0.596

Step-by-step explanation:

Since the weights of catfish are assumed to be normally distributed,

we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = weights of catfish.

µ = mean weight

σ = standard deviation

From the information given,

µ = 3.2 pounds

σ = 0.8 pound

The probability that a randomly selected catfish will weigh between 3 and 5.4 pounds is is expressed as

P(x ≤ 3 ≤ 5.4)

For x = 3

z = (3 - 3.2)/0.8 = - 0.25

Looking at the normal distribution table, the probability corresponding to the z score is 0.401

For x = 5.4

z = (5.4 - 3.2)/0.8 = 2.75

Looking at the normal distribution table, the probability corresponding to the z score is 0.997

Therefore,.

P(x ≤ 3 ≤ 5.4) = 0.997 - 0.401 = 0.596

4 0
2 years ago
According to the Rational Root Theorem, the following are potential roots of f(x) = 6x4 + 5x3 – 33x2 – 12x + 20. -5/2,-2, 1, 10/
stiks02 [169]
-5/2 is the answer. I just took the test and got it right.
8 0
2 years ago
Read 2 more answers
Suppose that the exam scores for students in a large university course are normally distributed with an unknown mean and standar
HACTEHA [7]

Answer:

Critical value t-score=2.701.

Step-by-step explanation:

When we calculate a confidence interval with an unknown population standard deviation, we estimate it from the sample standard deviation and use the t-score instead of the z-score.

The critical value for t depends on the level of confidence and the degrees of freedom.

If the sample size is 42, the degrees of freedom are:

df=n-1=42-1=41

For a confidence level of 99% and 41 degrees of freedom, the critical value of t is t=2.701.

6 0
2 years ago
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