Prepare a prototype residual plot for each of the following cases: (1) error variance decreases with X; (2) true regression func
tion is U shaped, but a linear regression function is fitted.
1 answer:
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Answer iiiiiiis -2d+c+12
Answer:
The solution in interval notation is:
.
The solution in inequality notation is:
.
Step-by-step explanation:
I think you are asking how to solve this for .
Keep in mind .
If then
.
Subtract on both sides:
Factor the difference of squares :
Simplify inside the factors:
The left hand side is a parabola that faces up. I know this because the degree is 2.
The zeros of the the parabola are at x=-6 and x=2/5.
We can solve x+6=0 and 5x-2=0 to reach that conclusion.
x+6=0
Subtract 6 on both sides:
x=-6
5x-2=0
Add 2 on both sides:
5x=2
Divide both sides by 5:
x=2/5
Since the parabola faces us and then we are looking at the interval from x=-6 to x=2/5 as our solution. That part is where the parabola is below the x-axis. We are looking for where it is below since it says the where is the parabola<0.
The solution in interval notation is:
.
The solution in inequality notation is:
.