Answer:
D.)
15040000 <= k <=19840000
Step-by-step explanation:
V = 1200 -0.00002k
Value V after one year falls in the range of $803.20 and $899.20.
Let's substract these values from 1200.
1200-803.20=396.80
1200-899.20=300.80
So it means that
0.00002k= 396.80
And
0.00002k= 300.80
So
0.00002k= 396.80
K= 396.80/0.00002
K= 19840000
And
0.00002k= 300.80
K = 300.80/0.00002
K= 15040000
So range is between
15040000 <= k <=19840000
-120 ÷ 15 = -8.
Hope this helps.
Answer:
Tyrone paid the higher markup rate.
Step-by-step explanation:
Tyrone and Terri both bought sofas with installment loans.
Tyrone bought his own with a sticker price of $1350 by paying $74 a month for 24 months. Therefore,
74 × 24 = $1776
The mark up = $1776 - $1350 = $426
Tyrone markup rate = 426/24 = $17.75 per month
Terri bought his own with sticker price of $950 by paying $52 a month for 24 months. Therefore,
52 × 24 = $1248
mark up = $1248 - $950 = $298
Terri markup rate = 298/24 = $12.4166666667 = $12.42 per month
The Range of a function is the set of all values that that function can take.
Given the sine function f(x)=sinx,
This function is the function which calculates the sine of the values of x.
According to the definition of the sine of an angle x in the unit circle,

,
so the sine of an angle is always larger or equal to -1, and smaller or equal to 1.
This means that the values that the sine function takes are any values between -1 and 1, inclusive.
This determines the Range of the sine function.
So the Range of the sine function is [-1, 1]
Answer: 20 unit.
Step-by-step explanation:
Since, Here the vertices of the rhombus defg are d(1, 4), e(4, 0), f(1, –4), and g(–2, 0).
Where, de, ef, fg, gd are sides of the rhombus defg.
By the distance formula,





Thus, the side of rhombus = 5
By the property of rhombus,
de = ef = fg = gd = 5 unit.
Thus, the perimeter of the given rhombus defg = de + ef + fg + gd = 5+5+5+5 = 20 unit