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marissa [1.9K]
2 years ago
13

Combine to create an equivalent expression -n + (-4) - (-4n) +6

Mathematics
1 answer:
Sav [38]2 years ago
3 0

Answer: The answer is 3n + 2

Step-by-step explanation: You will have to combine like terms:

=−n + −4 + 4n + 6

=(−n + 4n) + (−4 + 6)

=3n + 2

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One way to measure whether the trees in the Wade Tract are uniformly distributed is to examine the average location in the north
tatyana61 [14]

Answer:

Null hypothesis be H₀ : μ = 100

Alternative hypothesis Hₐ : μ < 100

There is sufficient statistical evidence to suggest that the average location of Wade Tract is 100

Step-by-step explanation:

Here we have;

Let our null hypothesis be H₀ : μ = 100 Average location of trees in the Wade Tract is 100

Our alternative hypothesis becomes Hₐ : μ < 100 at 95% confidence level

Proposed average location in Wade Tract, μ = 100

Sample mean, \bar x = 99.74

Standard deviation, s = 58

Sample size, n = 584

The t test formula is therefore;

t=\frac{\bar{x}-\mu }{\frac{s }{\sqrt{n}}}

Therefore, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025

We have t_{\alpha /2} = -1.65

Plugging in the values into the t test formula, we have t = -0.108338, from which the p-value is given as p = 0.4569 which is much more than the value of α, therefore, we accept the null hypothesis as follows;

There is sufficient statistical evidence to suggest that the average location of Wade Tract = 100.

7 0
2 years ago
While at a carnival, Andrew comes across a game that involves rolling a die. According to the game's rules, if the number rolled
Reptile [31]

Answer:

he can expect to lose 0.5$

Step-by-step explanation:

To solve this problem we must calculate the expected value of the game.

If x is a discrete random variable that represents the gain obtained when rolling a dice, then the expected value E is:

E =\sum xP (x)

When throwing a dice the possible values are:

x: 1→ -$9;  2→ $4;  3→ -$9;  4→ $8;  5→ -$9;  6→ $12

The probability of obtaining any of these numbers is:

p=\frac{1}{6}

The gain when obtaining an even number is twice the number.

The loss to get an odd number is $ 9

So the expected gain is:

E=-9*\frac{1}{6}-9*\frac{1}{6}-9*\frac{1}{6} + 4*\frac{1}{6} + 8*\frac{1}{6} + 12*\frac{1}{6}\\\\E =-27*\frac{1}{6} + 24*\frac{1}{6}\\\\E=-3*\frac{1}{6}\\\\E=-$0.5

4 0
2 years ago
3. Who set up their equation correctly for the following question?
melisa1 [442]
Heyy 3747484884 hwibdhdjens
5 0
2 years ago
The letters of the word mississippi are placed in a hat. what is the probability that the first two letters drawn are both i if
allochka39001 [22]
For the first letter drawn, there are no conditions/restrictions we need to consider. So, the number of ways to draw an i is:
\text{Draw(i): } \frac{4}{11}

For the second draw, the i is not replaced. That means, we've shrunk the sample space because we're dealing with less elements for the second draw. Firstly, one i disappears since we picked an "i" and there are 10 elements left, not 11.

Thus, to draw the second i, we have:
\text{Draw(ii): } \frac{3}{10}

\text{P(drawing 2 i's): } \frac{4}{11} \cdot \frac{3}{10} = \frac{12}{110} = \frac{6}{55}
3 0
2 years ago
A local PTA runs a fundraiser, selling lottery tickets for $5, offering 1 first prize of $100 and 5 second prizes worth $20 each
podryga [215]
100 tickets were sold.
The total amount of the tickets sold is = 5 * 100 = $500. 
First prize given = $100
Second prize worth = $20 * 5 = $100
Total worth of prize + $100 + $100 = $200.
Net amount of tickets sold = $500 - $200 = $300
Expected price of each ticket sold = $300/100 = 3.
Therefore, the real price of each ticket sold is $3.
6 0
2 years ago
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