Answer: The greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.
Step-by-step explanation:
Given: Lenin is preparing dinner plates. He has 12 pieces of chicken and 16 rolls.
To make all the plates identical without any food left over, the greatest number of plates Lenin can prepare = G.C.D.(12,16)=4
The number of pieces of chicken in each plate = 
The number of pieces of rolls in each plate = 
So, the greatest number of plates Lenin can prepare = 4
and there will be 3 chickens and 4 rolls in each plate.
Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,
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I believe the correct given equation is in the form of:
4 – 0.25 g + 0.5 h
Now we are to evaluate the equation with the given values:
g = 10 and h = 5
What this actually means is that to evaluate simply means
to calculate for the value of the equation by plugging in the values of the
variables. Therefore:
4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)
4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5
4 – 0.25 g + 0.5 h = 4
Therefore the value of the equation is:
4
Answer:
The last one
Step-by-step explanation:
The first one would be multiplication because you want to find the total thickness, the second one is division because it gives the total value and the amount of bags, the third one is addition because it gives you a starting value and says that they work this amount more in this month, and the last one is subtraction because he first pays with a gift card, and then with cash.
Hopefully that helped
You haven't provided the choices, therefore, I cannot provide an exact answer. However, I will help you with the concept.
For an order pair to be a solution to a system of equations, it has to satisfy <u>BOTH</u> equations. If it satisfies only one equation of the system or satisfy neither of the equations, the, it is not a solutions
<u><em>Examples:</em></u>
<u>System 1:</u>
x = y + 1
2x + 3y = 7
Let's check (2,1)
2 = 1 + 1 ........> equation 1 is satisfied
2(2) + 3(1) = 7 ......> equation 2 is satisfied
<u>(2,1) is a solution to this system</u>
<u>System 2:</u>
y = x + 3
y = x - 1
Let's check (2,1):
1 ≠ 2 + 3 ........> equation 1 isn't satisfied
1 = 2 - 1 ..........> equation 2 is satisfied
<u>(2,1) isn't a solution to this system</u>
<u>System 3:</u>
2y = 9 - 3x
3x + 2y = 9
Let's ceck (2,1):
2(1) ≠ 9 - 3(2) ..........> equation 1 isn't satisfied
3(2) + 2(1) ≠ 9 .........> equation 2 isn't satisfied
<u>(2,1) isn't a solution to this system
</u>
<u><em>Based on the above,</em></u> all you have to do is substitute with (2,1) in the system you have and pick the one where both equations are satisfied
Hope this helps :)
Answer:
29.15 km
Step-by-step explanation:
Given;
George walks; 25km west and then 15 km south
Resolving the directions to x and y axis;
North and South represent positive and negative y axis.
East and West represent positive and negative x axis respectively.
25km west
Rx = -25 km
15 km south
Ry = -15 km
The resultant displacement from the house is;
R = √(Rx^2 + Ry^2)
Substituting the values;
R = √((-15)^2 + (-25)^2)
R = √(225+625)
R = √(850)
R = 29.15 km
Therefore, he is 29.15 km from house