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2 years ago

11

A bag has 2 blue marbles, 3 red marbles, and 5 white marbles. Which events have a probability greater than One-fifth? Select thr

ee options.

2 answers:

ki77a [65]2 years ago

6 0

Answer:

B, D, E

Step-by-step explanation:

EDG 2020

AlladinOne [14]2 years ago

3 0

Answer:

first one and last two

Step-by-step explanation:

B)

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What other points are on the line of direct variation through (5, 12)? Check all that apply. (0, 0) (2.5, 6) (3, 10) (7.5, 18) (

aalyn [17]

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form $y/x=k$ or $y=kx$

in this problem we have

the point $(5,12)$ is on the line of direct variation

so

Find the constant of proportionality k

$y/x=k$ -------> substitute ------> $k=12/5$

the equation is

$y=\frac{12}{5}x$

Remember that

If a point is on the line of direct variation

then

the point must satisfy the equation of direct variation

we're proceeding to verify each point

<u>case A)</u> point $(0,0)$

$x=0\ y=0$

Substitute the value of x and y in the direct variation equation

$0=\frac{12}{5}*0$

$0=0$ -------> is true

therefore

the point $(0,0)$ is on the line of direct variation

<u>case B)</u> point $(2.5,6)$

$x=2.5\ y=6$

Substitute the value of x and y in the direct variation equation

$6=\frac{12}{5}*2.5$

$6=6$ -------> is true

therefore

the point $(2.5,6)$ is on the line of direct variation

<u>case C)</u> point $(3,10)$

$x=3\ y=10$

Substitute the value of x and y in the direct variation equation

$10=\frac{12}{5}*3$

$10=7.2$ -------> is not true

therefore

the point $(3,10)$ is not on the line of direct variation

<u>case D)</u> point $(7.5,18)$

$x=7.5\ y=18$

Substitute the value of x and y in the direct variation equation

$18=\frac{12}{5}*7.5$

$18=18$ -------> is true

therefore

the point $(7.5,18)$ is on the line of direct variation

<u>case E)</u> point $(12.5,24)$

$x=12.5\ y=24$

Substitute the value of x and y in the direct variation equation

$24=\frac{12}{5}*12.5$

$18=30$ -------> is not true

therefore

the point $(12.5,24)$ is not on the line of direct variation

<u>case F)</u> point $(15,36)$

$x=15\ y=36$

Substitute the value of x and y in the direct variation equation

$36=\frac{12}{5}*15$

$36=36$ -------> is true

therefore

the point $(15,36)$ is on the line of direct variation

therefore

<u>the answer is</u>

$(0,0)$

$(2.5,6)$

$(7.5,18)$

$(15,36)$

5 0

2 years ago

Read 2 more answers

Graph a line that contains the point (-5,-3)(−5,−3)left parenthesis, minus, 5, comma, minus, 3, right parenthesis and has a slop

dmitriy555 [2]

Point (-5,-3) Slope -2
Y - y1 = m (x - x1)
y + 3 = -2 (x + 5)
y + 3 = -2x - 10
y = -2x -13

The line will also go through the point (0, -13)

3 0

2 years ago

The histogram below shows the number of properties in a town that sold within certain time periods.

Tomtit [17]

Answer:

Option c) The scale on the y-axis misrepresents the difference in the heights of the bars.

Step-by-step explanation:

Given is a histogram that shows the number of properties in a town that are sold within certain periods.

On x axis is given number of days to sell and on y axis the number of properties

X axis is given in interval form with interval width 30 and on y axis scales are marked as 0,1,2....12,13 etc

The mistake is on y axis after 0, 10 is marked with unit distance from 0 but from 10 to 11 also distance is shown as 1 unit.

Hence correct option is

Option c) The scale on the y-axis misrepresents the difference in the heights of the bars.

7 0

2 years ago

Read 2 more answers

Hank bought 5 meters of ribbon for $4. The ribbon costs -$0.008, 0.08, $0.8- per -millimeter, centimeter, kilometer-. Choose one

aleksandrvk [35]

To determine the cost of each meter of the ribbon, we divide the cost for 5 meters of ribbon by 5. That is,
x = $4 / 5
where x is the cost of each meter. Simplifying will give us an answer of $0.8/m. Converting this to per mm.
($0.8/m) x (1 m/ 1000 mm)
= $0.0008/mm

5 0

2 years ago

Daniel is organizing his rock collection of 18 rocks into equal groups. How many possible ways can Daniel line up his rock colle

Colt1911 [192]

Answer:

The correct options are (2, 3 and 6).

Step-by-step explanation:

It is provided that Daniel has a rock collection of 18 rocks.

He wants to organize these 8 rocks into equal groups.

The factors of 18 are:

Factor (18): {1, 2, 3, 6, 9, 18}

A group is a selection of more than 1 items. So, there cannot be 18 groups.

And there cannot be 1 group, since then Daniel would not be organizing the rocks.

So, the possible ways Daniel line up his rock collection are {2, 3, 6 and 9}.

Thus, the correct options are (2, 3 and 6).

6 0

2 years ago