Answer:
7.5
Step-by-step explanation:
106% of $x = $7.95
In other words,
![\[\frac{106}{100}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%5C%5D)
of $x = 7.95
Multiplying both sides of the equation by ![\[\frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B100%7D%7B106%7D%5C%5D)
![\[\frac{106}{100} * \frac{100}{106}\]](https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7B106%7D%7B100%7D%20%2A%20%5Cfrac%7B100%7D%7B106%7D%5C%5D)
of x = 7.95 * ![[\frac{100}{106}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B100%7D%7B106%7D%5D)
=> x = ![[\frac{750}{100}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B750%7D%7B100%7D%5D)
=> x = ![[\frac{7.50}{1}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B7.50%7D%7B1%7D%5D)
=> x = 7.5
Validation: 106% of 7.5 = 7.95
Alrighty, so, if I remember correctly: For the first question you have 20 possible outcomes, 4 of which are multiples of 5. (5,10,15,20). This gives you 4/20, I multiplied both the numerator and denominator by 200 which then gave me 800/4000. Next I divided which gave me 0.2.
X cancels out, 8y + 2y is equal to 10y, and 26 + 14 is 40, so y=4
Answer:
Step-by-step explanation:
The question is incomplete. The complete question is:
An insurance company reported that, on average claims for a certain medical procedure are $942. an independent organization constructed a 95% confidence interval of ($930, $950) for the average amount claimed for the particular medical procedure. what conclusion best evaluates the truthfulness of the number reported by the insurance company?
a) with 95% certainty, the average claim for this medical procedure is $942.
b) with 95% certainty, the average claim for this medical procedure is not $942.
c) the confidence interval is consistent with an average claim of $942 for this medical procedure
Solution:
Confidence interval is used to express how confident we are that the population parameter that we are looking for is contained in a range of given values. Looking at the given confident interval, the lower limit is $930 and the upper limit is $950. We can see that the population mean, $942 lies within these values. The correct option would be
c) the confidence interval is consistent with an average claim of $942 for this medical procedure
