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1 year ago

Which expression represents the lateral surface area of the cone?

Mathematics

1 answer:

Brrunno [24]1 year ago

3 0

Answer:

Option "3" is the correct answer to the following question:

Step-by-step explanation:

Given:

Radius of cone (r) = 6 centimeter

height of cone (h) = 8 centimeter

slant height of cone (l) = 10 centimeter

Find:

Lateral surface area of the cone = ?

Computation:

⇒ Lateral surface area of the cone = $\pi$ rl

⇒ Lateral surface area of the cone = $\pi$ (6 centimeters) (10 centimeters)

⇒ Therefore, option "3" is the correct answer.

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A pizzeria will only deliver to locations within a certain distance of the pizzeria. The delivery region has an area of 36pi squ

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Step-by-step explanation:

she lives 10 miles away and the pizzeria only has a 6 mile radius.

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2 years ago

REASONING An even integer can be represented by the expression $2n$ , where $n$ is any integer. Find three consecutive even inte

san4es73 [151]

Answer:

First Integer = 16

Second Integer = 18

Third integer = 20

Step-by-step explanation:

An even integer is represented by 2n

Where n is any integer

Let :

First Integer = 2n - 2

Second Integer = 2n

Third integer = 2n + 2

The sum of three even consecutive numbers = 2n - 2 + 2n + 2n + 2

= 2n + 2n + 2n - 2 + 2 = 54

= 6n = 54

n = 54/6

n = 9

First Integer = 2n - 2 = 2(9) - 2

= 16

Second Integer = 2n = 2(9)

= 18

Third integer = 2n + 2 = 2(9) + 2

= 20

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2 years ago

How many possible outcomes, including both main effects and interaction effects, are possible for a factorial design with three

KIM [24]

Your answer will be <span>8</span>

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2 years ago

Two professors are applying for grants. Professor Jane has a probability of 0.61 of being funded. Professor Joe has probability

Anna11 [10]

Answer:

a. 0.1647;
b. 0.7153;
c. 0.4453.

Step-by-step explanation:

By definition, if two event $A$ and $B$ are independent, then

$P(A\cap B) = P(A) \cdot P(B)$ . ( $P(A\cap B)$ is the probability that the outcome of both event $A$ and event $B$ are true.)

Since the outcome of these two events are independent,

$\begin{aligned}P(\texttt{Jane} \cap \texttt{Joe}) &= P(\texttt{Jane}) \cdot P(\texttt{Joe})\\ &= 0.61 \times 0.27 \\&= 0.1647\end{aligned}$ .

The logic not operator $\lnot$ or the prime superscript $^{\prime}$ denotes that an event does not happen.

$P(\texttt{Jane}^{\prime}) = 1 - P(\texttt{Jane}) = 1- 0.61 = 0.39$ .

$P(\texttt{Joe}^{\prime}) = 1 - P(\texttt{Joe}) = 1- 0.27 = 0.73$ .

Since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}^{\prime}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that neither professor got funded:

$P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = P(\texttt{Jane}^{\prime}) \cdot P(\texttt{Joe}^{\prime}) = 0.39 \times 0.73 = 0.2847$ .

Probability that at least one professor got funded- in other words, it is not true that neither professor got funded:

$P((\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime})^{\prime}) = 1- P(\texttt{Jane}^{\prime} \cap \texttt{Joe}^{\prime}) = 0.7153$ .

Similarly, since the two events $\texttt{Jane}$ and $\texttt{Joe}$ , $\texttt{Jane}$ and $\texttt{Joe}^{\prime}$ are also independent. Probability that Jane but not Joe got funded:

$P(\texttt{Jane} \cap (\texttt{Joe}^{\prime})) = P(\texttt{Jane}) \cdot P(\texttt{Joe}^{\prime}) = 0.61 \times 0.73 = 0.4453$ .