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Amanda [17]
1 year ago
5

Sasha shared 20 muesli bars with three friends.

Mathematics
1 answer:
mestny [16]1 year ago
7 0

Answer: Sasha has 20 bars to start of with. Let's assume Sasha keeps 6 bars for herself. The problem says Sasha has twice as many bars as Hanna, so Hanna HAS to have 3 bars. The problem says Kyle got 3 more bars than Hanna, so 3+3=6, and Hannah got 2 less bars than Noah.. Noah has to have bars because 5-3=2

Sasha 6, Kyle 6, Noah 5, Hanna 3= 6+6+5+3=20

Step-by-step explanation:

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A group of friends are going ice skating. The price of admission is $3.25. As a group, they spent $14 on refreshments. If they s
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Start with $30.25. 
Subtract $14.00 to isolate the amount of money spent on admission. 
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Admission is 3.25 per person. Divide 16.25 by 3.25. 
16.25/3.25=5. 
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2 years ago
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Explain how you used the bar model in exercise 2 to solve the problem
lutik1710 [3]

We are given that Grandma has 14 red roses and 7 pink roses.

In order to represent them on bar modal, we need to make a bar with 14 identical sections for 14 red roses.

And for pink roses, we need to make a bar with 7 identical sections for 7 pink roses.

<em>From the bar graph, we can see that bar for red roses have 7 more boxes than bar of pink roses.</em>

<h3>Therefore,  she have 7 more red roses than pink roses.</h3>

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1 year ago
A daycare center charges a $75 enrollment fee plus $100 per week. Which of the following represents the cost of sending a child
Lorico [155]

Answer:

$1,475

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times 100 by 14 which is 1400

but then add 75 onto that

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1 year ago
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Find the dimensions of the box with volume 1728 cm3 that has minimal surface area. (Let x, y, and z be the dimensions of the box
Gala2k [10]

Answer:

The dimensions of the box are 12 cm , 12 cm , 12 cm

Step-by-step explanation:

Let x , y and z be the dimensions of box

Volume of box =xyz=1728

z=\frac{1728}{xy}

Surface area of box = 2xy+2yz+2xz=2xy+2y(\frac{1728}{xy})+2x(\frac{1728}{xy})

Let f(x,y)=2xy+2(\frac{1728}{x})+2(\frac{1728}{y})

To get minimal surface area

\frac{\partial f}{\partial x}=0 and \frac{\partial f}{\partial y}=0

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial x}=0

2y-2(\frac{1728}{x^2})=0

y=\frac{1728}{x^2} ----1

\frac{\partial(2xy+2(\frac{1728}{x})+2(\frac{1728}{y}))}{\partial y}=0

2x-2(\frac{1728}{y^2})=0\\x=\frac{1728}{y^2}  \\y^2=\frac{1728}{x}

Using 1

(\frac{1728}{x^2} )^2=\frac{1728}{x}

x=0 and x^3=1728

Side can never be 0

So,x^3=1728

x=12

y=\frac{1728}{x^2} \\y=\frac{1728}{12^2}

y=12

z=\frac{1728}{xy}\\z=\frac{1728}{(12)(12)}

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5 0
1 year ago
At the beginning of the school year, Jamie had $500 in her savings account. She wants to have at least $200 left in the account
mario62 [17]

Answer:

Jamie should have reversed the inequality when using the division property of inequality.

Step-by-step explanation:

Jamie wrote

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500 − 30x ≥ 200

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500-500-30x ≥ 200-500

-30x ≥ -300

Divide both sides by -30

x <or= 10

8 0
2 years ago
Read 2 more answers
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