Answer:
I suppose it should be
6b² and (6b²)²
or
6b² and 36
Step-by-step explanation:
(a+b)² = a² + 2ab + b²
therefore
(6b²+2a)² = (6b²)² + 12ab² + 4a²
The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>
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The difference of finish times has a mean of
μ = 105 -98 = 7 . . . . minutes
and a variance of
σ² = 10² +15² = 325 . . . . minutes²
Using a probability calculator, we find the probability to be
p(-5 < x < 5) ≈ 0.2030
3x^3 – 5x^2 – 12x + 20
= (3x^3 – 5x^2) – (12x - 20)
= x^2(3x - 5) - 4(3x - 5)
= (3x - 5)(x^2 - 4)
= (3x - 5)(x + 2)(x - 2)
Factors: (3x - 5), (x + 2), and (x - 2)
Answer:
D.) 3x – 5